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4 years ago

An 8 kg mass moving at 8 m/s collides with a 6 kg mass

Physics

1 answer:

steposvetlana [31]4 years ago

3 0

Answer:

10 m/s

Explanation:

Momentum before collision = momentum after collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(8 kg)(8 m/s) + (6 kg)(6 m/s) = (8 kg)(5 m/s) + (6 kg) v

64 kg m/s + 36 kg m/s = 40 kg m/s + (6 kg) v

60 kg m/s = (6 kg) v

v = 10 m/s

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The fictional rocket ship Adventure is measured to be 65 m long by the ship's captain inside the rocket.When the rocket moves pa

kipiarov [429]

Answer:

1.04 s

Explanation:

The computation is shown below:

As we know that

t = t' × 1 ÷ (√(1 - (v/c)^2)

here

v = 0.5c

t = 1.20 -s

So,

1.20 = t' × 1 ÷ (√(1 - (0.5/c)^2)

1.20 = t' × 1 ÷ (√(1 - (0.5)^2)

1.20 = t' ÷ √0.75

1.20 = t' ÷ 0.866

t' = 0.866 × 1.20

= 1.04 s

The above formula should be applied

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3 years ago

The outer planets _____.all have rings

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4 years ago

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3 years ago

A stubborn 130 kg pig sits down and refuses to move. to drag the pig to the barn, the exasperated farmer ties a rope around the

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4 years ago

The wavelength of light beam B is twice the wavelength of light beam B. The energy of a photon in beam A is:

julia-pushkina [17]

Corrected question: The wavelength of light beam A is twice the wavelength of light beam B. The energy of a photon in beam A is:

Answer:

Explanation:

Energy = hc/λ

λ(A) =2λ(B)...................equation 1

We will solve for the ratio of energy of A to energy of B.which is

$\frac{E_{A} }{E_{B} }$

=(hc/λA) ÷ (hc/λB)

referring to equation 1 we have

=(hc/2λB) ÷ (hc/λB)

=hc/2λB) × (λB/hc)

= λB/2λB

$\frac{E_{A} }{E_{B} }$ =1/2

${E_{A} = \frac{1}{2} E_{B}$

The energy of A is half of B

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3 years ago