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patriot [66]
3 years ago
15

An 8 kg mass moving at 8 m/s collides with a 6 kg mass

Physics
1 answer:
steposvetlana [31]3 years ago
3 0

Answer:

10 m/s

Explanation:

Momentum before collision = momentum after collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(8 kg)(8 m/s) + (6 kg)(6 m/s) = (8 kg)(5 m/s) + (6 kg) v

64 kg m/s + 36 kg m/s = 40 kg m/s + (6 kg) v

60 kg m/s = (6 kg) v

v = 10 m/s

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Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2.

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3 years ago
An object is falling from a height of 7.5 meters. At what height will it’s velocity be 7 meters/second?
Nady [450]
One of the equations of gravity is this:
{v}^{2} = {u}^{2} + 2gh
Where v = final velocity which is 7m/s
u = initial velocity which is 0 for objects falling from a height
g = acceleration due to gravity and it is approximately 10m/s^2. It's a constant so pretty much remember this number. It's positive since the work being done is caused by gravity (in other words, it's falling down). It can also be negative if the work being down is against gravity (in other words, it's going up)
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Substitute for the values and you should have something like this
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3 years ago
Does friction always oppose relative motion?
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Can the velocity of a body revese the direction when acceleration is constant?
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