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3 years ago

An 8 kg mass moving at 8 m/s collides with a 6 kg mass

Physics

1 answer:

steposvetlana [31]3 years ago

3 0

Answer:

10 m/s

Explanation:

Momentum before collision = momentum after collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(8 kg)(8 m/s) + (6 kg)(6 m/s) = (8 kg)(5 m/s) + (6 kg) v

64 kg m/s + 36 kg m/s = 40 kg m/s + (6 kg) v

60 kg m/s = (6 kg) v

v = 10 m/s

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a object with a mass of 70 kilograms is supported at a height 8 meters above the ground.what's the potential energy of the objec

Agata [3.3K]

Potential Energy = mgh,

where m = mass in kg, g ≈ 10 m/s², h = height above ground = 8 m

PE = mgh

= 70*10*8 = 5600 J

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3 years ago

Ammonia at 10◦c with a mass of 10 kg is in a piston/cylinder assembly with an initial volume of 1 m3. the piston initially resti

jeyben [28]

Here mass is floating on the piston at equilibrium

So it will have constant pressure always remains constant

So final pressure is same as initial pressure = 900 kPa

now we can say

$\frac{V_1}{V_2} = \frac{T_1}{T_2}$

$\frac{1}{V_2} = \frac{273+10}{273+50}$

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so final pressure is 900 kPa and final volume is 1.14 m^3

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3 years ago

If this decay has half-life of 2 years, how many years would it take for 10.8 g Protactinium-231 to remain given an initial mass

sergij07 [2.7K]

Answer:

Time = 6 years

Explanation:

First, we will calculate the no. of half life periods required to reduce the mass of Protactinium to the given value:

$m' = \frac{m}{2^{n} } \\\\2^n = \frac{m}{m'}$

where,

n = no. of half-life periods = ?

m = initial mass = 86.3 g

m' = remaining mass = 10.8 g

Therefore,

$2^n = \frac{86.3\ g}{10.8\ g}\\\\2^n = 8\\2^n = 2^3$

Since the bases are the same. Therefore equating powers:

n = 3

Now we calculate the time:

$Time = (n)(Half-Life)\\Time =(3)(2\ years)$

<u>Time = 6 years</u>

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3 years ago

Which of the following equations defines the law of conservation of energy?

loris [4]

NONE of those choices defines the law of conservation of energy,
and none even describes it. It's as if these choices belong to
a whole different question.

In fact, none of the choices is even a true statement by itself !

A statement that defines the law of conservation of energy
would have to say something like this:

The total amount of energy in any closed system is constant.
The total amount of energy after any event or process is the
same as the total amount was before it.

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3 years ago

An atomic nucleus has a charge of +40e. an electron is 10-9 m from the nucleus. what is the force on the electron?

sergiy2304 [10]

The electron charge is equal to $-e=-1.6\cdot 10^{-19}C$ . The atomic nucleus of the problem has a charge of $+40 e=40\cdot (1.6\cdot 10^{-19}C)=6.4\cdot 10^{-18}C$ . The distance between the nucleus and the electron is $r=10^{-9}m$ , so we can calculate the electrostatic (Coulomb) force between the two:
$F=k_e \frac{(-e)(+40e) }{r^2} =8.99\cdot 10^9 Nm^2C^{-2} \frac{(-1.6\cdot 10^{-19}C)(6.4\cdot 10^{-18}C)}{(10^{-9}m)^2} =$
$=-9.2 \cdot 10^{-9} N$
which is attractive, since the two charges have opposite sign.

4 0

3 years ago