Answer:
![9.96\cdot 10^{-10}J](https://tex.z-dn.net/?f=9.96%5Ccdot%2010%5E%7B-10%7DJ)
Explanation:
The capacitance of the parallel-plate capacitor is given by
![C=\epsilon_0 k \frac{A}{d}](https://tex.z-dn.net/?f=C%3D%5Cepsilon_0%20k%20%5Cfrac%7BA%7D%7Bd%7D)
where
ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity
k = 3.00 is the dielectric constant
is the area of the plates
d = 9.00 mm = 0.009 m is the separation between the plates
Substituting,
![C=(8.85\cdot 10^{-12}F/m)(3.00 ) \frac{30.0\cdot 10^{-4} m^2}{0.009 m}=8.85\cdot 10^{-12} F](https://tex.z-dn.net/?f=C%3D%288.85%5Ccdot%2010%5E%7B-12%7DF%2Fm%29%283.00%20%29%20%5Cfrac%7B30.0%5Ccdot%2010%5E%7B-4%7D%20m%5E2%7D%7B0.009%20m%7D%3D8.85%5Ccdot%2010%5E%7B-12%7D%20F)
Now we can calculate the energy of the capacitor, given by:
![U=\frac{1}{2}CV^2](https://tex.z-dn.net/?f=U%3D%5Cfrac%7B1%7D%7B2%7DCV%5E2)
where
C is the capacitance
V = 15.0 V is the potential difference
Substituting,
![U=\frac{1}{2}(8.85\cdot 10^{-12}F)(15.0 V)^2=9.96\cdot 10^{-10}J](https://tex.z-dn.net/?f=U%3D%5Cfrac%7B1%7D%7B2%7D%288.85%5Ccdot%2010%5E%7B-12%7DF%29%2815.0%20V%29%5E2%3D9.96%5Ccdot%2010%5E%7B-10%7DJ)
We can conclude that it is a longitudinal wave because the wave is traveling through a medium displacing particles<span>
</span>
Gravity affet everything and it touches nothing.
Hope this helps!
Answer:
0.16 m
Explanation:
A rectangular gasoline tank can hold 50.0 kg of gasoline when full, and the density of gasoline is 6.8 × 10² kg/m³. We can find the volume occupied by the gasoline (volume of the tank).
50.0 kg × (1 m³/6.8 × 10² kg) = 0.074 m³
The volume of the rectangular tank is:
volume = width × length × depth
depth = volume / width × length
depth = 0.074 m³ / 0.500 m × 0.900 m
depth = 0.16 m
A joule is a unit of energy.