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zubka84 [21]
4 years ago
15

PLEASSE HELP WILL MARK BRAINLIEST!!!!!!!!!!

Physics
1 answer:
faust18 [17]4 years ago
6 0
They are halogen elements, or nonmetallic elements in the same GROUP, specifically group 17
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When the moon is between the earth and the sun what moon phase will this be
Aleksandr [31]

Answer:  The new moon phase occurs when the Moon is directly between the Earth and Sun. A solar eclipse can only happen at new moon. A waxing crescent moon is when the Moon looks like crescent and the crescent increases ("waxes") in size from one day to the next. This phase is usually only seen in the west.

3 0
3 years ago
A vehicle travels from a 30m marker to a 100m marker. What is the change in distance
alexgriva [62]

70 meters is your answer

Note that the beginning is the 30 meter mark, and the ending is the 100 meter mark. Subtract the beginning amount from the end:

100 - 30 = 70

The vehicle traveled 70 meters.

~

8 0
3 years ago
*An inductor is capable of dissipating 50W of heat energy when a current 0.8A flows through it at a certain frequency. Calculate
ale4655 [162]
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8 0
4 years ago
Which element has 24 protons
TEA [102]

<u>Answer:</u>

<u>Answer:Chromium</u>

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4 0
3 years ago
A projectile of mass 6.8 kg kg is shot horizontally with an initial speed of 14.5 m/s from a height of 26.7 m above a flat deser
sleet_krkn [62]

Answer:

Explanation:

Given

mass of projectile m=6.8\ kg

initial horizontal speed u_x=14.5\ m/s

height h=26.7\ m

Considering vertical motion

velocity gained by projectile during 26.7 m motion

v^2-u^2=2 as

v=final velocity

u=initial velocity

a=acceleration

s=displacement

v^2-(0)^2=2\times (9.8)\times (26.7)

v=\sqrt{523.32}

v=22.87\ m/s

Horizontal velocity will remain same as there is no acceleration

final velocity v_{net}=\sqrt{(v)^2+(u_x)^2}

v_{net}=\sqrt{733.57}=27.08\ m/s

Initial kinetic Energy K_i=\frac{1}{2}mu_x^2

K_i=\frac{1}{2}\times 6.8\times (14.5)^2=714.85\ J

Final Kinetic Energy K_f=\frac{1}{2}mv_{net}^2

K_f=\frac{1}{2}\times 6.8\times (27.08)^2

K_f=2493.30\ J

Work done by all the force is equal to change in kinetic Energy of object

Work done by gravity is W_g

W_g=\Delta K

W_g=2493.30-714.85=1778.45\ J  

8 0
3 years ago
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