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antiseptic1488 [7]
2 years ago
6

Help me please........................

Physics
1 answer:
stepan [7]2 years ago
3 0

Answer:

Left

Explanation:

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You are a support technician working in a data closet in a remote office. You suspect that a connectivity problem is related to
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crimping tool

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This is a tool employed in affixing a connector to the end of a network cable.

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A) an electron has an initial speed of 226000 m/s. if it undergoes an acceleration of 4.0 x 1014 m/s2, how long will it take to
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initial speed of 226000 m/s

acceleration of 4.0 x 1014 m/s2,

speed of 781000 m/s

What is Acceleration?

  • Acceleration is a rate of change of velocity with respect to time with respect to direction and speed.
  • A point or an object moving in a straight line is accelerated if it speeds up or slows down.
  • Acceleration formula can be written as,

                    a = (v - u ) / t m/s²

As we have to find the time taken, the formula can be altered as,

t = \frac{v-u}{a}

where, t - time taken to reach a final speed

v - final velocity

u - initial velocity

a - acceleration.

Substituting all the given values,

t =\frac{781000 - 226000} {4* 1014}

= 1.3875 × 10⁻⁹ seconds.

So, taken to reach the final speed is found to be 1.3 × 10⁻⁹ 8iH..

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1 year ago
1. A box contains 10 blue chips. 5 red chips, and 15 yellow chips. Find the odds of choosing the
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Answer:

Explanation:

Blue: 10/30

Red: 5/30

Yellow: 15/30

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2 years ago
A projectile is launched from the ground with an initial velocity of 12ms at an angle of 30° above the horizontal. The projectil
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vi^{2}sin2thita/g =12^{2}sin2[30]/9.8=12.7Answer:

Explanation:

range is given as

6 0
3 years ago
Read 2 more answers
Multiple-Concept Example 9 reviews the concepts that are important in this problem. A drag racer, starting from rest, speeds up
Mademuasel [1]

Answer:

V = 90.51 m/s

Explanation:

From the given information:

Initial speed (u) = 0

Distance (S) = 391 m

Acceleration (a) = 18.9 m/s²

Using the relation for the equation of motion:

v² - u² = 2as

v² - 0² = 2as

v² = 2as

v = \sqrt{2as}

v = \sqrt{2*18.9*391}

v = 121.57 m/s

After the parachute opens:

The initial velocity = 121.57 m/ss

Distance S' = 332 m

Acceleration = -9.92 m/s²

How fast is the racer can be determined by using the relation:

V=  \sqrt{v^2 + 2aS'}

V = \sqrt{121.57^2+ 2 (-9.92)(332)}

V = 90.51 m/s

6 0
3 years ago
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