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pychu [463]
3 years ago
5

A geochemist in the field takes a 36.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X.

He notes the temperature of the pool, 170 C, and caps the sample carefully. Back in the lab, the geochemist first dilutes the sample with distilled water to 500. mL. Then he filters it and evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 3.96 g.
Using only the information above, can you calculate yes the solubility of X in water at 17.0 C? If you said yes, calculate it.
Chemistry
1 answer:
NeTakaya3 years ago
3 0

Answer:

solubility of X in water at 17.0 ^{0}\textrm{C} is 0.11 g/mL.

Explanation:

Yes, the solubility of X in water at 17.0 ^{0}\textrm{C} can be calculated using the information given.

Let's assume solubility of X in water at 17.0 ^{0}\textrm{C} is y g/mL

The geochemist ultimately got 3.96 g of crystals of X after evaporating the diluted solution made by diluting the 36.0 mL of stock solution.

So, solubility of X in 1 mL of water = y g

Hence, solubility of X in 36.0 mL of water = 36y g

So, 36y = 3.96

   or, y = \frac{3.96}{36} = 0.11

Hence solubility of X in water at 17.0 ^{0}\textrm{C} is 0.11 g/mL.

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How do you balance redox equations in acidic solutions?
Anuta_ua [19.1K]

Answer:

First, balance the half-reactions

Second, equalize the electrons

Third,add two reaction equations to get final answer

Explanation:

For example

H₂C₂0₄ + MnO⁻₄ ---------->CO₂+Mn²⁺

(i) Balancing the half reactions

H₂C₂O₄-------->2CO₂+2H⁺+2e⁻

5e⁻ +8H⁺+MnO₄⁻----------->Mn²⁺+4H₂O

(ii)

Equalizing the electrons

5H₂C₂O₄--------->10CO₂+10H⁺+10e⁻  ---here there is a factor of 5

10e⁻+16H⁺+2MnO₄⁻--------->2Mn²⁺+8H₂O -----here there is a factor of 2

(iii)

Add the two where electrons and some Hydrogen ions will cancel out

5H₂C₂O₄+6H⁺+2MnO₄⁻---->10CO₂+2Mn²⁺+8H₂O

7 0
3 years ago
when 6.25 grams of pure iron are allowed to react with oxygen , a black oxide forms. if the product weighs 8.15 g, what is the e
erik [133]
We are given with the mass of  pure iron that reacts with oxygen to form an oxide which has a given mass as well. the mass of oxygen reacted is 8.15-6.25 g or 1.9 grams. THen we convert the mass of the reactants to moles. Iron is equal to 0.1119 moles and oxygen is equal to 0.1188. We divide each number to the less amount. Hence iron is 1 and oxygen is approx 1. The empirical formula hence is FeO or ferrous oxide or Iron (II) oxide.
5 0
3 years ago
When a compound such as X2Z4 is created, what would be the<br> correct simplified chemical formula?
Shtirlitz [24]

Answer:

XZ2

Explanation:

There are different ways in which compounds can be represented. Broadly, we have three different types of formula;

- Structural formular: This shows how th atoms in te compound are connected to each other.

- Molecular formular: This shows the actual number of atoms of element present in the compound

- Empirical Formular: This is the simplest formular of a compound. It basically shows the number of atoms in simple ration to each other.

This question requires us to input the empirical formular;

X2Z4

The ratio of the elements is; 2 : 4 which can be simplified into 1 : 2

This means the empirical formular is XZ2

6 0
3 years ago
student in chemistry 150-02 weighed out 55.5g of octane c8h18 and allowed it to react with oxygen, o2 the product formed were ca
Tasya [4]

Answer:

C8H8 + 10O2 → 8CO2 + 4H2O

Explanation:

unbalanced reaction:

C8H8 + O2 → CO2 + H2O

balanced for semireactions:

(1) 16H2O + C8H8 → 8CO2 + 40H+

(2) 10(4H+ + O2 → 2H2O)

⇒ 40H+ + 10O2 → 20H2O

(1) + (2):

balanced reaction:

⇒ C8H8 + 10O2 → 8CO2 + 4H2O

                      8 - C - 8

                     20 - O2 - 20

                      8 - H - 8

3 0
3 years ago
Many classic experiments have given us indirect evidence of the nature of the atom. Which of the experiments below did not give
taurus [48]

The Rutherford experiment proved the Thomson “plum-pudding” model of the atom to be essentially correct did not give the results described and is denoted as option A.

<h3>What is Thomson “plum-pudding” model?</h3>

This model was proposed by J.J Thomson in which referred an atom as a sphere of positive charge, and negatively charged electrons are embedded in it to balance the total positive charge.

This model was incorrect and the Rutherford atomic model was adopted in which he described the electrons orbits about a tiny positive nucleus.

The nucleus contains protons and neutrons instead thereby making it the correct choice.

Read more about Atom here brainly.com/question/6258301

#SPJ1

The options include the following:

a.The Rutherford experiment proved the Thomson “plum-pudding” model of the atom to be essentially correct.

b.The Rutherford experiment was useful in determining the nuclear charge on the atom.

c.Milikan’s oil-drop experiment showed that the charge on any particle was a simple multiple of the charge on the electron.

d.The electric discharge tube proved that electrons have a negative charge

4 0
1 year ago
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