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galben [10]
3 years ago
13

The atomic mass number of aluminum is 26.98. If you had 1.34 x 1025 atoms of aluminum, how much would they all weigh?

Chemistry
1 answer:
a_sh-v [17]3 years ago
3 0

Answer:

601 gram

Explanation:

1st we should know how may moles are there in 1.34 X 10 25 atoms

 # moles of Al = # of atoms / # of Avogadro's num

                      = 1.34 X 10 25/ 6.12X10 23 =

                       = 22.26 mol of AL

 so mass of AL = moles x m.wt

                          =22.26 x 26.98 = 600.55 = 601 gram

DONE

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Rhodium crystallizes in a face-centered cubic unit cell. The radius of a rhodium atom is 135 pm. Determine the density of rhodiu
Deffense [45]

Answer:

Density of unit cell ( rhodium) = 12.279 g/cm³

Explanation:

Given that:

The radius (r) of a rhodium atom = 135 pm

The atomic mass of rhodium = 102.90 amu

For a face-centered cubic unit cell,

r = \dfrac{a}{2\sqrt{2}}

where;

a = edge length.

Making "a" the subject of the formula:

a = 2 \sqrt{2} \times r

a = 2 \times 1.414 \times 135 \ pm

a = 381.8 pm

to cm, we get:

a = 381.8 × 10⁻¹⁰ cm

However, recall that:

density \ of \ unit \ cell = \dfrac{mass \ of \ unit \ cell}{volume \ of \unit \ cell}

where;

mass of unit cell = mass of atom × numbers of atoms per unit cell

Also;

mass\  of\ atom =\dfrac{ atomic \ mass}{Avogadro  \  number}

mass\  of\ atom =\dfrac{ 102.9}{6.023 \times 10^{23}}

Recall also that number of atoms in a unit cell for a  face-centered cubic = 4

So;

mass \ of \ unit \ cell= \dfrac{102.90}{6.023 \times 10^{23}}\times 4

mass of unit cell = 6.83380375 × 10⁻²² g

Density  \ of  \ unit \  cell = \dfrac{6.83380375 \times 10^{-22}}{(381.8\times 10^{-10})^3}

Density of unit cell ( rhodium) = 12.279 g/cm³

3 0
3 years ago
If 3.3167 moles of Al are produced, how many moles of<br> AlCl3 were reacted?<br> I
tresset_1 [31]

Answer:

3.3167 moles Of AlCl3

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3Ca + 2AlCl3 —> 3CaCl2 + 2Al

From the balanced equation above,

2 moles of AlCl3 reacted to produce 2 moles of Al.

Finally, we shall obtained the number of moles of AlCl3 that reacted to produce 3.3167 moles of Al as follow:

From the balanced equation above,

2 moles of AlCl3 reacted to produce 2 moles of Al.

Therefore, 3.3167 moles Of AlCl3 will also react to produce 3.3167 moles of Al.

Thus, 3.3167 moles Of AlCl3 is needed for the reaction.

8 0
3 years ago
Question 3 of 5
rusak2 [61]

Answer:

A. More mass

C. Shorter distance between them

Explanation:

The two characteristics of a body experiencing greater gravitational force are that they have mass and a shorter distance between them.

This is conformity with Newton's law of universal gravitation.

The law states that "every object attracts one another with a force that is directly proportional to their masses and inversely proportional to the square of the distance between them".

This law implies that the more the mass of two bodies, the more the gravitational force of attraction. And that the shorter the square of the distance between them, the more the attraction.

7 0
3 years ago
Consider the reversible reaction A ( g ) − ⇀ ↽ − B ( g ) Which K values would indicate that there is more B than A at equilibriu
oksano4ka [1.4K]

Answer:

5000 and 8\times 10^{7} indicate that there is more B than A at equilibrium

Explanation:

For the given reaction: K=\frac{[B]}{[A]}

where [B] and [A] represents equilibrium concentration B and A respectively. K represents equilibrium constant

More B than A at equilibrium means, [B] > [A]

So, K=\frac{[B]}{[A]}>1

As, both 5000 and 8\times 10^{7} are greater than 1 therefore these two K values indicate that there is more B than A at equilibrium

4 0
3 years ago
What are the possible phenotypes of the offspring?
Tanzania [10]

Answer:freckles with straight hair

Explanation:

6 0
3 years ago
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