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galben [10]
3 years ago
13

The atomic mass number of aluminum is 26.98. If you had 1.34 x 1025 atoms of aluminum, how much would they all weigh?

Chemistry
1 answer:
a_sh-v [17]3 years ago
3 0

Answer:

601 gram

Explanation:

1st we should know how may moles are there in 1.34 X 10 25 atoms

 # moles of Al = # of atoms / # of Avogadro's num

                      = 1.34 X 10 25/ 6.12X10 23 =

                       = 22.26 mol of AL

 so mass of AL = moles x m.wt

                          =22.26 x 26.98 = 600.55 = 601 gram

DONE

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A 12.5 g sample of granite initially at 82.0 oc is immersed into 25.0 g of water that is initially at 22.0 oc. what is the final
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Given this information, we can say that:

12.5 g * 0.790 J / g ˚C * (T2 – 82 ˚C) = - 25.0 g * 4.18 J / g ˚C * (T2 – 22 ˚C)

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