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3 years ago

Which congruency statement is true?

Mathematics

2 answers:

nordsb [41]3 years ago

5 0

bc = fg

the letters should correspond with each other

(b is in the middle of abc and f is in the middle efg; c & g are both at the end)

just olya [345]3 years ago

3 0

For congruency the related sides need to be similar, which means they letters need to be in the correct order.

AB would be EF, BC would be FG and AC would be EG

This would make the correct answer BC ≅ FG

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Please solve for M<PRQ

MakcuM [25]

Answer:

$m\angle PRQ =49\degree$

Step-by-step explanation:

$m\angle PSQ = 360\degree - (128\degree + 134\degree )$

$m\angle PSQ = 360\degree - 262\degree$

$m\angle PSQ = 98\degree$

Now, by inscribed angle theorem:

$m\angle PRQ = \frac{1}{2} \times m\angle PSQ$

$m\angle PRQ = \frac{1}{2} \times 98\degree$

$m\angle PRQ =49\degree$

5 0

3 years ago

Please please help me!!!!!!!

Jlenok [28]

Answer:

Step-by-step explanation:

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7 0

3 years ago

-50 Points-<br> If segment AC and segment BC are tangent to circle O, find the value of x.

Shkiper50 [21]

Answer:

x = 170 deg

Step-by-step explanation:

A tangent to a circle is perpendicular to the radius of the circle at the point of tangency. That means that in quadrilateral AOBC, angles A and B are right angles and measure 90 deg.

The sum of the measures of the angles of an n-sided polygon is

(n - 2)180 deg

In this case, n = 4, so

(4 - 2)180 deg = 360 deg

m<A + m<O + m<B + m<C = 360

90 + x + 90 + 10 = 360

x + 190 = 360

x = 170

Answer: 170 deg

4 0

3 years ago

Read 2 more answers

Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then