Answer:
the magnitude of the electron's acceleration a at that moment =
Explanation:
The expression for the magnetic field is :
where:
= permeability of free space =
I = current in the wire = 12.7 A
r = distance from the wire to the field point = 3.47 cm =
The magnetic force exerted in the electrond passing through the straight conducting wire is:
F = Bvgsinθ
where :
B = magnetic field =
v = speed of light = (30.5 % )
q = charge of electrons =
θ = angle between speed of electron & field = 90°
F = () × (30.5 % ) × () × ( sin 90°)
F =
From Newtons second Law ;
F = ma
where m = mass =
Thus, the magnitude of the electron's acceleration a at that moment =
Due to the conservation of electric charge, the current is uniform throughout an electrical circuit.
The answer is B.
Answer:
The platform move before coming to rest again 0.045 m far
Explanation:
Given
Ball is in motion
M (Platform mass + 2 people mass)
V (recoil velocity of the platform)
m (ball mass)
v (velocity ball)
MV + mv = 0
Distance of the platform movement is
t (time that the ball is in the air)
x = Vt
t =
Knowing the platform and the ball are moving while the ball is in the air
x =
Also knowing that
This way,
x = =
The minus sign means the displacement of the platform is in opposite direction to the displacement of the ball.
<u>Answer:</u>
<em>Thunderbird is 995.157 meters behind the Mercedes</em>
<u>Explanation:</u>
It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird decided to take a pit stop and slows down for 250 m. She spent 5 seconds in the pit stop.
Here final velocity
initial velocity distance
Distance covered in the slowing down phase =
The car is in the pit stop for 5s
After restart it accelerates for 350 m to reach the earlier velocity 71 m/s
total time=
Distance covered by the Mercedes Benz during this time is given by
Distance covered by the Thunderbird during this time=
Difference between distance covered by the Mercedes and Thunderbird
=
Thus the Mercedes is 995.157 m ahead of the Thunderbird.