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Alex17521 [72]
3 years ago
6

A fisherman noticed that a float makes 30 oscillations in 15 seconds. The distance between two consecutive crests is 2 m. What i

s the period and frequency of the wave? What is the wave speed?
Physics
1 answer:
never [62]3 years ago
8 0

Answer:

Period T = 0.5 s

Frequency F = 2 Hz

Wave speed V = 4 m/s

Explanation:

Given that the

Number of oscillations = 30

Time taken = 15 seconds

The distance between two consecutive crests is called wavelength

Wavelength = 2m

Period is the ratio of time and the number of oscillations

Period T = 15/30 = 0.5 seconds

Frequency F is the reciprocal of period. That is,

F = 1/T

F = 1/0.5 = 2Hz

Wave speed V is the product of frequency and wavelength

V = 2 × 2 = 4m/s

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Gala2k [10]

Option C

Both technicians are correct

<h3><u>Explanation:</u></h3>

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The automatic systems are electric systems that want different inputs from sensors that intimate climate circumstances to obtain the aspired temperature. Vacuum actuators and/or electric motors control the air doors/valves in these systems.

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3 years ago
A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through
Svet_ta [14]

Answer:

The speed is \sqrt{2}v_{0}.

(a) is correct option.

Explanation:

Given that,

Potential difference V= V_{0}

Speed v = v_{o}

If it were accelerated instead

Potential difference V'=2V_{0}

We need to calculate the speed

Using formula of initial work done on proton

W = q V

We know that,

\Delta W=\Delta K.E

q V=\dfrac{1}{2}mv^2

Put the value into the formula

q V_{0}=\dfrac{1}{2}mv_{0}^2

v_{0}^2=\dfrac{2qV_{0}}{m}....(I)

If it were accelerated instead through a potential difference of 2 V_{0}, then it would gain a speed will be given as :

Using an above formula,

v_{0}'^2=\dfrac{2qV_{0}}{m}

Put the value of V_{0}

v_{0}'^2=\dfrac{2q\times2V_{0}}{m}

v_{0}'=\sqrt{\dfrac{4qV_{0}}{m}}

v_{0}'=\sqrt{2}v_{0}

Hence, The speed is \sqrt{2}v_{0}.

6 0
3 years ago
How is social media changing the world as we know it?
Vika [28.1K]

Answer:

Social media has helped many businesses grow and promote itself, and has helped people find a better way to connect and communicate with one another. On the other hand, it's also provided many people with problems involving mental health, emotional insecurities, and waste of time

Explanation:

what they said is correct

4 0
3 years ago
CHEGG 42 mT magnetic field points due west. If a proton of kinetic energy 9 x 10-12 J enters this field in an upward direction,
alexdok [17]

Answer:

The  magnitude of the Force is  F = 697 *10^{-15}N  and the direction is South  

Explanation:

From the question we are told that

         The magnetic field point due west and since East point toward the positive x -axis(i)  then this magnetic field would be mathematically represented as

                \= B = 42(-i)mT = 42*10^{-3} (-i) T

Now from the question we are told that the kinetic energy is

             KE = 9*10^{-12}J

Now this kinetic energy can be mathematically represented as

                  KE = \frac{1}{2}mv^2

Where m is the mass of proton which has a general value of

           m = 1.67*10^{-27}kg

Now making the subject of the formula

                v = \sqrt{\frac{KE}{0.5 * m} }

Substituting values we have

               v = \sqrt{\frac{9*10^{-12}}{0.5 * 1.67*10^{-27}} }

                 = 10.37*10^7m/s

Now from the question we are told that proton is moving upward which is in the positive z direction so the velocity of the proton would be in the positive

So the velocity would be

            \= v = 10.37*10^{7} \r k \ m/s

Now the magnetic Force can be mathematically represented as

          \= F = q \= v * \=  B

Where q is the charge on the proton which has a general value of  q =1.6*10^{-19}C

Now substituting the value

          \= F = 1.6*10^{-19 } * (10.37 *10^7) \r k * (42 *10^{-3})(-i)

              = 697*10^{-15} J

Now according to Fleming's left hand rule the direction of the magnetic force is south toward the negative Y - direction (-j)

So the force can be denoted as

                 \= F = 697*10^{-15}(-j) N

             

             

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Q.1- A 3000 cm3 tank contain O2 gas at 20 °C and a gauge pressure of 2.5 x 106 Pa. Find the mass of oxygen in the tank.
exis [7]
20c because te mass of the object is larger than the table
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3 years ago
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