Answer:
x = 14
EHF = 15 degree GHF = 75 degree
Step-by-step explanation:
(x+1) + (5x+5) = 90
(x+5x)+ (1+5) = 90
6x + 6 = 90
6x = 90-6
6x = 84
x = 84/6
x = 14
EHF + GHF = 90 degree
EHF = x+1
= 14 + 1 = 15
= 15 degree
GHF = 5x+5
= 14 x 5 (+5) = 70 + 5
= 75 degree
EHF = 15 degree GHF = 75 degree
Answer:
b. about 63.9 units and 41.0 units
Step-by-step explanation:
In question ∠a= 29° and Side of a= 15 and b= 20
Using sine rule of congruence of triangle.
⇒ 
⇒ 
Using value of sin 29°
⇒ 
Cross multiplying both side.
⇒ Sin B= 
∴ B= 41°
Now, we have the degree for ∠B= 41°.
Next, lets find the ∠C
∵ we know the sum total of angle of triangle is 180°
∴∠A+∠B+∠C= 180°
⇒ 
subtracting both side by 70°
∴∠C= 110°
Now, again using the sine rule to find the side of c.
⇒
Using the value of sine and cross multiplying both side.
⇒ C= 
∴ Side C= 28.92.
Now, finding perimeter of angle of triangle
Perimeter of triangle= a+b+c
Perimeter of triangle= 
∴ Perimeter of triangle= 63.9 units
Answer:
227.5 grams
Step-by-step explanation:
We know that a single 10p coin weights 6.5 g
Now we want to find the weight of a bag of 10p coins, such that the net value is £3.50 (where the weight of the bag is neglected)
The value of a 10p coin is £0.10
So the first thing we need to find, is how many coins there are in the bag.
To find that, we need to find the quotient between the total value and the value of a single coin:
£3.50/£0.10 = 35
So in the bag, we have 35 coins, and each one of them weighs 6.5 grams
Then the total weight is 35 times 6.5 grams:
35*6.5 g= 227.5 grams
The easy part is isolating the absolute-value term:
5 + 7 |2<em>x</em> - 1| = -44
7 |2<em>x</em> - 1| = -49
|2<em>x</em> - 1| = -7
Remember that the absolute value function returns a positive number that you can think of as the "size" of that number, or the positive distance between that number and zero. If <em>x</em> is a positive number, its absolute value is the same number, |<em>x</em>| = <em>x</em>. But if <em>x</em> is negative, then the absolute value returns its negative, |<em>x</em>| = -<em>x</em>, which makes it positive. (If <em>x</em> = 0, you can use either result, since -0 is still 0.)
The important thing to take from this is that there are 2 cases to consider: is the expression in the absolute value positive, or is it negative?
• If 2<em>x</em> - 1 > 0, then |2<em>x</em> - 1| = 2<em>x</em> - 1. Then the equation becomes
2<em>x</em> - 1 = -7
2<em>x</em> = -6
<em>x</em> = -3
• If 2<em>x</em> - 1 < 0, then |2<em>x</em> - 1| = - (2<em>x</em> - 1) = 1 - 2<em>x</em>. Then
1 - 2<em>x</em> = -7
-2<em>x</em> = -8
<em>x</em> = 4
Answer:
i’m struggling on this
Step-by-step explanation:
if anybody gets the answer please let me know
