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m_a_m_a [10]
2 years ago
14

A 2.83 g piece of zinc (density = 7.14 g/ml) is added to a graduated cylinder that contains 12.13 ml H2O. What will be the final

volume reading on the graduated cylinder, in ml?
Chemistry
1 answer:
Maslowich2 years ago
3 0

The final volume reading on the graduated cylinder is 12.52ml

Density = mass / volume

Volume = mass / density

Volume of zinc = 2.83/7.14

Volume of zinc = 0.3963

Initial volume = 12.13 ml

Total volume = initial volume+ volume of zinc

Total volume = 12.13 + 0.3963

Total volume = 12.5263 = 12.52 ml

To know more about volume to go the given link :

brainly.com/question/11510153

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The empirical formula of a compound is CH2O and its molecular weight is 90.09 g/mol. Determine the molecular formula.
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Answer : The molecular formula of the compound will be, C_{3}H_{6}O_3

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

As we are given that the empirical formula of a compound is CH_2O and the molar mass of compound is, 90.09 gram/mol.

The empirical mass of CH_2O = 1(12) + 2(1) + 1(16) = 30 g/eq

n=\frac{\text{molecular mass}}{\text{empirical mass}}

n=\frac{90.09}{30}=3

Molecular formula = (CH_2O)_n=(CH_2O)_3=C_{3}H_{6}O_3

Thus, the molecular formula of the compound will be, C_{3}H_{6}O_3

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artcher [175]

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