<span> (6y^2 + 4y + 5) – (3 – 7y + y^2)
= </span><span> 6y^2 + 4y + 5 – 3 + 7y - y^2
= 5</span>y^2 + 11y + 2
hope it helps
Answer:
I do not know the answer to this question
Step-by-step explanation:
Answer: The height of the new player is 210 cm
Step-by-step explanation: The previous mean of the entire team has been calculated as 200.3
What this means is that, we have a summation of the observed data and a summation of the frequency of data.
The mean was calculated as
Sum FX/Sum F = 200.3
Where Sum FX is 2604 and Sum F is 13
However, our calculation should now read thus,
Sum FX/Sum F = 201 {where 201 is the new mean}
By cross multiplication we now have
Sum FX = Sum F x 201
Remember that a new member has joined the team so our Sum F is now 14 and we can now express it as thus
Sum FX = 14 x 201
Sum FX = 2814
If the summation of the observed data after adding a new team member is now 2814, then the addition to the previous observed data would be
2814 - 2604 = 210
So the height of the new member added to the team is 210 cm.
3/7 * -2 1/5 = (turn ur mixed number into an improper fraction)
3/7 * - 11/5 = (now just multiply straight across)
(3 * -11) / (7 * 5) = -33/35 <====
Answer:
y=5x+25
y=5(12)+25
y=85
Step-by-step explanation:
