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LuckyWell [14K]
3 years ago
13

A driver without a seat belt getting thrown from the car in a collision is an example of Newton’s?

Physics
1 answer:
kupik [55]3 years ago
5 0
Newton’s first law. An object stays in motion unless acted on by an external force or in this case the driver was in motion but the sudden crash stoped the car but not the driver
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Which of the following solutions should be chosen to help restore an ecosystem naturally? A. reintroducing an animal to the ecos
jolli1 [7]

Answer:

A. reintroducing an animal to the ecosystem

Explanation:

As generally, all know that for restoring an ecosystem naturally, it requires reintroduction of an animal to the ecosystem. As though it helps in reimposing the ecosystem back, and also helps to improve our ecosystem in natural surroundings, natural terrain, and population density. Basically reintroducing an animal is also required for the balancing of the ecosystem. As everything requires a properly balanced nature.

7 0
3 years ago
A 18Ω resistance is cut into three equal parts and connected in parallel. Find the equivalent resistance of the combination.
Andrew [12]

Answer:

2Ω

Explanation:

If a 18Ω resistance is cut into three equal parts each of the resistance will be 18Ω/3 = 6Ω

Equivalent ratio in parallel is expressed as:

1/R = 1/6 + 1/6 + 1/6

1/R = 3/6

Cross multiply

3R = 6

R = 6/3

R = 2Ω

Hence the required equivalent resistance is 2Ω

5 0
3 years ago
A car is accelerated from 40 m/s to 48 m/s in 6.5 seconds. What is the magnitude of the car’s
pantera1 [17]

Answer:

Explanation:

AVerage acceleration is the cjange in velocity with time

a = v-u/t

v is the final velocity = 48m/s

u is the initial velocity = 40m/s

t is the time = 6.5s

a = 48-40/6.5

a = 8/6.5

a = 1.23m/s²

Hence the magnitude of the car’s  average acceleration during this period is 1.23m/s²

4 0
3 years ago
(03.02 LC)
ratelena [41]

Answer:

O Adenine and guanine

Explanation:

i think tell me if im rong

5 0
3 years ago
During the first 6 years of its operation, the Hubble Space Telescope circled the Earth 37,000 times, for a total of 1,280,000,0
oksian1 [2.3K]

Answer:

v = 384km/min

Explanation:

In order to calculate the speed of the Hubble space telescope, you first calculate the distance that Hubble travels for one orbit.

You know that 37000 times the orbit of Hubble are 1,280,000,000 km. Then, for one orbit you have:

d=\frac{1,280,000,000km}{37,000}=34,594.59km

You know that one orbit is completed by Hubble on 90 min. You use the following formula to calculate the speed:

v=\frac{d}{t}=\frac{34,594.59km}{90min}=384.38\frac{km}{min}\approx384\frac{km}{min}

hence, the speed of the Hubble is approximately 384km/min

5 0
3 years ago
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