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Katyanochek1 [597]
3 years ago
7

Why do some elements (ex: Neon) have a large number of spectral lines, compared to Hydrogen?

Chemistry
1 answer:
Doss [256]3 years ago
7 0
<span> The production of absorption and emission lines . The first theory of the atom to provide an explanation of </span>hydrogen's<span> observed </span>spectral lines<span>  those two energy levels, the electron </span>can<span> exist only in </span>certain<span> sharply defined . The </span>number<span> of protons in the nucleus of an atom determines the </span>element<span> that </span>
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A sodium atom can easily lose an electron. What happens to this electron?
meriva

Answer:

A.it is converted into thermal energy

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3 years ago
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4 years ago
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Which of the following has no electrical charge?
Shtirlitz [24]

Answer:

neutron

Explanation

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4 0
3 years ago
onvert the value of Kc to a value of Kp for the following reaction: N2(g)+3H2(g)⇌2NH3(g) Kc = 0.50 at 400 °C.
ale4655 [162]

Answer:

K_p= 0.00016

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

N_2_{(g)}+3H_2_{(g)}\rightleftharpoons2NH_3_{(g)}

Given: Kc = 0.50

Temperature = 400^oC=[400+273]K=673K

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (2)-(3+1) = -2

Thus, Kp is:

K_p= 0.50\times (0.082057\times 673)^{-2}

K_p= 0.00016

6 0
3 years ago
For the following reaction, identify the element that was oxidized, the element that was reduced, and the reducing agent. Give a
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<span>For this reaction, oxidation number of Carbon in CO would be +2 while oxidation number of carbon in CO2 would be +4 and so this means that carbon has oxidized. Oxidation number of nitrogen in NO is +2. While oxidation number of nitrogen in N2 is 0 so this means that nitrogen had reduced. The reducing agent is the one which provides electrons by oxidizing itself so in this case; CO is the reducing agent while the C in CO oxidized to produce electrons. </span><span>I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.</span>

6 0
3 years ago
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