Answer: high pressure because it's stable
Explanation:
Air mass is volume of air which has stable temperature, humidity and pressure horizontally. Over time, each air mass acquires properties of the region by residing over same part of a surface.
Areas of low pressure and high pressure occur where there is warm air and cold air respectively. An air mass usually forms over an area of high pressure. Warm air rises up and cold air takes its place. Warm air has low density and low pressure where as cold air has high density and pressure and therefore, sinks to the bottom. This is a stable condition. The movement of air mass is responsible for maintenance of temperature conditions on Earth.
Answer : The partial pressure of
and
is, 216.5 mmHg and 649.5 mmHg
Explanation :
According to the Dalton's Law, the partial pressure exerted by component 'i' in a gas mixture is equal to the product of the mole fraction of the component and the total pressure.
Formula used :
![p_i=X_i\times p_T](https://tex.z-dn.net/?f=p_i%3DX_i%5Ctimes%20p_T)
![X_i=\frac{n_i}{n_T}](https://tex.z-dn.net/?f=X_i%3D%5Cfrac%7Bn_i%7D%7Bn_T%7D)
So,
![p_i=\frac{n_i}{n_T}\times p_T](https://tex.z-dn.net/?f=p_i%3D%5Cfrac%7Bn_i%7D%7Bn_T%7D%5Ctimes%20p_T)
where,
= partial pressure of gas
= mole fraction of gas
= total pressure of gas
= moles of gas
= total moles of gas
The balanced decomposition of ammonia reaction will be:
![2NH_3\rightarrow N_2+3H_2](https://tex.z-dn.net/?f=2NH_3%5Crightarrow%20N_2%2B3H_2)
Now we have to determine the partial pressure of
and ![H_2](https://tex.z-dn.net/?f=H_2)
![p_{N_2}=\frac{n_{N_2}}{n_T}\times p_T](https://tex.z-dn.net/?f=p_%7BN_2%7D%3D%5Cfrac%7Bn_%7BN_2%7D%7D%7Bn_T%7D%5Ctimes%20p_T)
Given:
![n_{N_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg](https://tex.z-dn.net/?f=n_%7BN_2%7D%3D1%5C%5C%5C%5Cn_%7BH_2%7D%3D3%5C%5C%5C%5Cn_%7BT%7D%3D4%5C%5C%5C%5Cp_T%3D866mmHg)
![p_{N_2}=\frac{1}{4}\times (866mmHg)=216.5mmHg](https://tex.z-dn.net/?f=p_%7BN_2%7D%3D%5Cfrac%7B1%7D%7B4%7D%5Ctimes%20%28866mmHg%29%3D216.5mmHg)
and,
![p_{H_2}=\frac{n_{H_2}}{n_T}\times p_T](https://tex.z-dn.net/?f=p_%7BH_2%7D%3D%5Cfrac%7Bn_%7BH_2%7D%7D%7Bn_T%7D%5Ctimes%20p_T)
Given:
![n_{H_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg](https://tex.z-dn.net/?f=n_%7BH_2%7D%3D1%5C%5C%5C%5Cn_%7BH_2%7D%3D3%5C%5C%5C%5Cn_%7BT%7D%3D4%5C%5C%5C%5Cp_T%3D866mmHg)
![p_{H_2}=\frac{3}{4}\times (866mmHg)=649.5mmHg](https://tex.z-dn.net/?f=p_%7BH_2%7D%3D%5Cfrac%7B3%7D%7B4%7D%5Ctimes%20%28866mmHg%29%3D649.5mmHg)
Thus, the partial pressure of
and
is, 216.5 mmHg and 649.5 mmHg
Answer:
7. 4H₂O
Elements: Hydrogen, Oxygen
Number of molecules: 4
Number of elements: 8 H, 4 O
Number of Atoms: 12
Explanation:
The elements are determined by the their symbol i.e. H = hydrogen.
The number of molecules is determined by the coefficient ( the number in front of everything, in this case 4).
The number of elements is determined by the coefficient and the subscripts. Multiply the coefficient by the subscript after each element. When there is no subscript, it is equal to 1. 4H₂ = 4x2 = 8; 4O = 4x1 = 4.
The number of atoms is all the individual elements added together. 8+4 = 12.
Answer:
3.4g of Al
Explanation:
you would need to start with 3.4 g of Al