Answer:
The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.
Explanation:
- To solve this problem, we use Clausius Clapeyron equation: ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂).
- The first case: P₁ = 1 atm = 760 torr and T₁ = 451.0 K.
- The second case: P₂ = <em>??? needed to be calculated</em> and T₂ = 61.5 °C = 334.5 K.
- ΔHvap = 48.8 KJ/mole = 48.8 x 10³ J/mole and R = 8.314 J/mole.K.
- Now, ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂)
- ln(760 torr /P₂) = (48.8 x 10³ J/mole / 8.314 J/mole.K) (1/451 K - 1/334.5 K)
- ln(760 torr /P₂) = (5869.62) (-7.722 x 10⁻⁴) = -4.53.
- (760 torr /P₂) = 0.01075
- Then, P₂ = (760 torr) / (0.01075) = 70691.73 torr.
So, The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.
It's asking what are the conditions of the water when the three types of fishes overlap. the three kids of fishes overlap over in the middle which is D. mild temperatures, some suspended particles, flows at medium speed.
Answer:
yes i will help
txt me. down and show what is the. project
Answer:
B. False
Explanation:
the reaction is
H₂0 + O₂ = H₂O
as addition of oxygen means burning in the system which means heating or energy is necessary for the reactants. SO the reaction is spontaneous and exothermic .
As according to second law of thermodynamics
the change in enthalpy is greater than or equal to zero when the reaction is spontaneous, so enthalpy will increase in the above reaction.
H2 burning in O2 to form H2O (l) is an example of a system where the entropy of the universe increases.
