1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vfiekz [6]
3 years ago
6

The pH of a 0.0001 M NaOH solution is (note: For strong bases such as NaOH, the hydroxide ion concentration is the same as the c

oncentration
of the base)
10
5
а
Ob
о с
Od
3
8
Chemistry
1 answer:
Eddi Din [679]3 years ago
3 0

Answer:

pH = 10

Explanation:

As the problem states, with strong bases<em> the hydroxide ion concentration [OH⁻] is equal to the concentration of the base</em>. That means that in this case:

  • [OH⁻] = 0.0001 M

With [OH⁻] we can <u>calculate the pOH of the solution</u>:

  • pOH = -log[OH⁻]
  • pOH = 4

Then with the pOH, we <u>calculate the pH of the solution</u>:

  • pH = 14 - pOH
  • pH = 10
You might be interested in
This is an underground level where the ground becomes saturated with water.
ozzi

Answer: Pumping can affect the level of the water table. In an aquifer, the soil and rock is saturated with water.

Explanation:

8 0
3 years ago
Read 2 more answers
6th grade science . :((
Nadusha1986 [10]

Answer:

C- private

Explanation:

This event seems to be exclusive. That is why it is private.

3 0
3 years ago
How many molecules are in 85g of silver nitrate?
maksim [4K]
<h3>Answer:</h3>

3.0 × 10²³ molecules AgNO₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Writing Compounds
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

85 g AgNO₃ (silver nitrate)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 85 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{6.022 \cdot 10^{23} \ molecules \ AgNO_3}{1 \ mol \ AgNO_3})
  2. Multiply/Divide:                                                                                                \displaystyle 3.01313 \cdot 10^{23} \ molecules \ AgNO_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.01313 × 10²³ molecules AgNO₃ ≈ 3.0 × 10²³ molecules AgNO₃

6 0
2 years ago
What is the purpose of the uninoculated control tubes used in the oxidation fermentation test?
Black_prince [1.1K]
The purpose of the uninoculated control tubes used in this test is that two uninoculated control tubes are needed to show the results of the medium in both aerobic and anaerobic environments. It is used to show it is sterile and also as a color comparison, used also to show that the medium remains green under both conditions. 
5 0
3 years ago
Explain how you were able to use your knowledge of how different types of blood react with anti A, anti B, and anti Rh antibodie
dybincka [34]

Depending upon the clumping reaction with anti A , anti B and anti Rh antibodies the blood types are determined.

Explanation:

Agglutination (clumping) will occur when blood that contains the particular antigen is mixed with the particular antibody.

A+ have Agglutination with Anti-A ,Anti-Rh and No agglutination with Anti-B.

A- have Agglutination with Anti-A and No agglutination with Anti-B and Anti-Rh.

B+ have Agglutination with Anti-B Anti-Rh and No agglutination with Anti-A.

B- have Agglutination with Anti-B and No agglutination with Anti-B and Anti-Rh.

Rh+ have Agglutination with Anti-A and Anti-Rh and No agglutination with Anti-B.

Rh- have No Agglutination with Anti-A and Anti-B and Anti-Rh.

3 0
3 years ago
Other questions:
  • You are trying to determine the volume of the balloon needed to match the density of the air in the lab. You know that if you ca
    13·1 answer
  • Wafting the air above a chemical is one way to it directly
    6·1 answer
  • 4. Calorimetry can be used to determine the specific heat capacity of different substances (not just metals). Using the online c
    10·1 answer
  • Which statement is true about oxygen?
    14·1 answer
  • Zirconium orbital diagram
    9·1 answer
  • WILL GIVE BRAINLIEST TO PERSON WHO ANSWERS FASTEST AND CORRECT BUT ANY ANSWERS TO JUST GET POINTS WILL GET REPORTED AND DELETED
    5·2 answers
  • NaOH dissociation equation​
    8·1 answer
  • MATH AND SCIENCE
    12·1 answer
  • An element emits light at a wavelength of 584 nm. What is the energy of the photon with that wavelength?
    10·1 answer
  • Calculate the volume in (L) of 1.13x10^5 grams of liquid sodium which has a density of 0.929g/cm3
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!