Answer:
1.0x10^-4
Explanation:
First, in order to do this, we need to calculate the volume of 1 simple atom of Ar. Using the formula of the volume of a sphere we have the following
Converting A to cm:
0.97 * 1x10^-8 = 9.7x10^-9 cm
Now the volume:
V = 4/3π(9.7x10^-9)³
V = 3.82x10^-24 cm³
We know that 1 cm³ is 1 mL, and 1 L is 1000 mL so:
V = 3.82x10^-24 mL / 1000 = 3.82x10^-27 L
Now, using avogadro's number, we should get the total volume of all atoms of Ar so:
3.82x10^-27 * 6.02x10^23 = 2.3x10^-3 L
Finally, at STP the volume of an ideal gas is 22.4 L so:
2.3x10^-3 / 22.4 = 1.03x10^-4
With two significant figure, it would be 1.0x10^-4
Answer:
F=m(a) 3.111
Explanation:
So to find the acceleration you would have to reverse the problem, a=F/m
The speed of both cars is the same ... 80 km per hour.
But their velocities are different, because DIRECTION is part of velocity, and their directions are different.
The frequency of an oscillation is equal to the reciprocal of the period:

where
f is the frequency
T is the period
In our problem, the period is T=8.01 s, therefore the corresponding frequency is
Answer:
The average induced emf is 29.06 V
Explanation:
Given;
radius of the circular loop, r = 12.0 cm = 0.12 m
magnetic field strength, B = 1.8 T
time interval = 2.8 ms = 0.0028 s
Area of the circular loop, A = πr² = π (0.12)² = 0.0452 m²

where;
B is magnetic field
A is area
t is time
substitute the values given in the above equation to calculate the average emf that will be induced in the wire loop during the extraction process.

Therefore, the average induced emf is 29.06 V