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Alona [7]
3 years ago
12

An object falls from a hovering helicopter and hits the ground at a speed of 30m per seconds. how long does it take the object t

o reach the ground and how far does it fall? sketch a velocity-time graph for the object ( ignore air resistance
​
Physics
1 answer:
Harman [31]3 years ago
4 0

Answer:

45.9m

Explanation:

Given parameters:

Final velocity  = 30m/s

Initial velocity  = 0m/s

Unknown:

Time it takes for the object of fall  = ?

Height of fall = ?

Solution:

For the first problem, we use the equation below to solve for t;

      V = U + gt

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

t is the time taken

          30  = 0 + 9.8 x t

          30  = 9.8t

            t  = \frac{30}{9.8}  = 3.1s

Now, height of fall;

  V² = U²  + 2gH

   30² = 0² + 2 x 9.8 x H

   900  = 19.6H

      H  = 45.9m

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1.
Anna35 [415]

Answer:

430.

Explanation:

If we know that 0.5 is half of a whole number, then we can simply understand that we need to 215 x 2 to get our answer.

3 0
3 years ago
Calculate the power transfer when a pump moves 50kg of water through a vertical height of 8meters in 5seconds (take g =10meters
Vika [28.1K]

Hi there!

Recall the following relationships:

W = \Delta U = mg\Delta h\\\\P = \frac{W}{t}

W = Work (J)

U = Potential Energy (J)

m = mass (kg)

g = acceleration due to gravity (9.8 m/s²)

h = height (m)

t = time (s)

Begin by calculating the work:

W = 50(10)(8) = 4000 J

Now, divide by the time to solve for power:

P = \frac{4000}{5} = \boxed{800W}

**W is the unit for power (Watts).  Be careful not to get the two confused.

4 0
3 years ago
A heating element is made by maintaining a potential difference of 75.0 V across the length of a Nichrome wire that has a 3.83 ×
Tju [1.3M]

Answer:

Explanation:

power of a heating element = V² / R where V is voltage and R is resistance

putting in the values

5200 = 75² / R

R = 1.082 ohm

Formula for resistance

R = ρ L / S , ρ is resistivity , L is length and S is cross sectional area

1.082 = 5 x 10⁻⁷ x L / (3.83 x 10⁻⁶)

L = 8.29 m

b )

power of a heating element = V² / R , R is new resistance

5200 = 120² / R

R = 2.77 ohm

R = ρ L / S , ρ is resistivity , L is length and S is cross sectional area

2.77 = 5 x 10⁻⁷ x L / (3.83 x 10⁻⁶)

L = 21.22 m

4 0
3 years ago
A mass attached to a spring oscillates in simple harmonic motion with an amplitude of 10 cm. When the mass is 5.0 cm from its eq
timama [110]

When the mass is 5.0 cm from its equilibrium point, the percentage of its energy that is kinetic is 75%.

<h3>Total energy of the mass</h3>

The total energy possessed by the mass under the simple harmonic motion  is calculated as follows;

U = ¹/₂kA²

where;

  • k is the spring constant
  • A is the amplitude of the oscillation
<h3>Potential energy of the mass at 5 cm from equilibrium point</h3>

P.E = ¹/₂k(Δx)²

<h3>Kinetic energy of mass</h3>

K.E = U - P.E

K.E = ¹/₂kA² - ¹/₂k(Δx)²

<h3>Percentage of its energy that is kinetic</h3>

K.E (\%) = \frac{U - P.E}{U} \times 100\%\\\\K.E (\%) =\frac{\frac{1}{2}kA^2 - \frac{1}{2}k(\Delta x)^2 }{\frac{1}{2}kA^2} \times 100\%\\\\K.E (\%) = \frac{A^2 - (\Delta x)^2}{A^2} \times 100\%\\\\K.E (\%) = \frac{10^2 - (10-5)^2}{10^2} \times 100\%\\\\K.E (\%) = \frac{10^2 - 5^2}{10^2} \times 100\%\\\\K.E (\%) = 75\%

Thus, when the mass is 5.0 cm from its equilibrium point, the percentage of its energy that is kinetic is 75%.

Learn more about kinetic energy here: brainly.com/question/25959744

3 0
2 years ago
HELPPPPP !!!!
Nataly [62]

Your answer is C)

a)t=2.78 sec

b)R=835.03 m

c)

Explanation:

Given that

h= 38 m

u=300 m/s

here given that

The finally y=0

So

t=2.78 sec

The horizontal distance,R

R= u x t

R=300 x 2.78

R=835.03 m

The vertical component of velocity before the strike

4 0
3 years ago
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