What happens to a low-mass star after helium flash?

A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward p

Alexxx [7]

Answer:1) the total distance is the sum of the two distances

60 km + 45 km = 105 km

2) The displacement is the net movement, or the difference between the initial position and the final position

Call x the initial position, then the final position is x + [60km - 45km]

And the displacement is x + (60km - 45km) - x =60km -45 km = 15 km

Explanation:

6 0

2 years ago

According to Newton's first law of motion, what would happen to a car traveling at a constant velocity of 55 MPH to the west in

mart [117]

Explanation:

Newton's first law of motion says that an object will be at rest or it will be in motion until an unbalanced force acts on it.
In this case, a car traveling at a constant velocity of 55 mph to the west in the absence of an unbalanced force.

It would mean that the car will continue to move with a constant velocity of 55 mph to the west due to Newton's first law of motion.

6 0

2 years ago

A mass of 100 kg is pulled by a 392 N force in the +X direction along a rough surface (uk=0.4) with uniform velocity v=20 m/s. W

alexdok [17]

Answer:

The total work done will be zero.

Explanation:

Given that,

Mass = 100 kg

Force = 392 N

Velocity = 20 m/s

Distance s= 10 m

We need to calculate the work done

Using balance equation

The net force will be

$F'=F-\mu mg$

$F'=392-0.4\times100\times9.8$

$F'=0$

The net force is zero.

Hence, The total work done will be zero by all forces on the object.

5 0

2 years ago

Two parallel square metal plates that are 1.6 cm apart and 24 cm on each side carry equal but opposite charges uniformly spread

Fiesta28 [93]

The amount of extra electrons present on the negative surface is

57.2 x $10^{10}$ .

Distance =1.6 cm

Side = 24 cm

Electric field = 18000 N/C

Calculating the capacitance in the metal plates is necessary.

Using the capacitance formula

$C=\frac{e_{0}A }{d}$

Putting the value

C = 8.85 x $10^{-12}$ x (24 x $10^{-2}$ $)^{2}$ /1.6 x $10^{-2}$

C = 0.318 x $10^{-10}$ F

<h3>Calculation of potential</h3>

V = Ed

V = 18000 x 1.6 x $10^{-2}$ V

V = 288 V

<h3>Calculation of charge</h3>

Q = CV

Q = 0.318 x $10^{-10}$ x 288

Q = 91.54 x $10^{-10}$ C

Charge on the both the plates

Q = +91.54 x $10^{-10}$

Q = - 91.54 x $10^{-10}$

Calculation of excess electrons on the negative surface:

n = q/e

n = 91.54 x $10^{-10}$ / 1.6 x $10^{-19}$

n = 57.2 x $10^{10}$ electrons

Hence, the number of excess electrons on the negative surface is

57.2 x $10^{10}$ .

Learn more about capacitance here:

brainly.com/question/14746225

#SPJ4

8 0

8 months ago

A ball droped from a building. How fast is it traveling after falling 3.55s

algol [13]

Answer:

d = 61.75 m

Explanation:

Given that,

A ball droped from a building.

We need to find how fast is it traveling after falling 3.55 s.

As it is dropped, its initial velocity is equal to 0.

Let d is the distance it covers after falling 3.55 s.

We can use second equation of motion to find d.

$d=ut+\dfrac{1}{2}at^2$

Here, u = 0 and a =g

$d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 9.8\times (3.55)^2\\\\d=61.75\ m$

So, it will cover 61.75 m after falling 3.55 seconds.

4 0

3 years ago