Answer: D.
Explanation: Just took the quiz.
Answer:
The child will take 5.952 seconds to travel from the top of the hill to the bottom.
Explanation:
Given that the child accelerates uniformly and that both initial (
) and final speeds (
), measured in meters per second, and acceleration (
), measured in meters per square second, are known, we proceed to use the following kinematic equation to determine the time taken to travel from the top of the hill to the bottom (
), measured in seconds, is:
(1)
If we know that
,
and
, then the time taken is:

The child will take 5.952 seconds to travel from the top of the hill to the bottom.
Answer:

Explanation:
From the question we are told that:
Number of turns 

Conductor each with side length 
Current 
Magnetic field
Generally the equation for the total magnetic moment M is mathematically given by



I attached my work and highlighted my answers. Hope it makes sense! please comment back with any questions if anything is still unclear! :)
Answer:
Vmax=11.53 m/s
Explanation:
from conservation of energy

Spring potential energy =potential energy due to elevation
0.5*k*x²= mg
=mgh
0.5*k*2.3²= 430*9.81*6
k=9568.92 N/m
For safety reason
k"=1.13 *k= 1.13*9568.92
k"=10812.88 N/m
agsin from conservation of energy

spring potential energy=change in kinetic energy
0.5*k"*x²=0.5*m*
10812.88 *2.3²=430*
=11.53 m/s