Answer:
It will take 313.376 sec to raise temperature to boiling point
Explanation:
We have given that potential difference V = 120 Volt
Current i = 4.50 A
So resistance 
Heat flow in resistor will be equal to 
It is given that this heat is used for boiling the water
Mass of the water = 0.525 kg = 525 gram
Specific heat of water 4.186 J/gram/°C
Initial temperature is given as 23°C
Boiling temperature of water = 100°C
So change in temperature = 100-23 = 77°C
Heat required to raise the temperature of water 
So 
t = 313.376 sec
So it will take 313.376 sec to raise temperature to boiling point
Answer:
t=0.47s
Explanation:
the ball has uniformly accelerated movement due to gravity
Vo=initial speed=4.6m/s
g=gravity=-9.8m/s^2
Vf=final speed=0, the player must wait for the ball to stop. so the final speed will be 0
we can use the following ecuation
T=(Vf-Vo)/g
T=(0-4.6)/-9.8m/s^2
T=0.47s
The complex, highly technical formula for capacitors is
<em>Q = C V</em>
Charge = (capacitance) (voltage)
Charge = (3 F) (24 V)
<em>Charge = 72 Coulombs</em>
The positive plate of the capacitor is missing 72 coulombs worth of electrons. They were sucked into positive terminal of the battery stack.
The negative plate of the capacitor has 72 coulombs worth of extra electrons. They came from the negative terminal of the battery stack.
You should be aware that this is a humongous amount of charge ! An average <u><em>lightning bolt</em></u>, where electrons flow between a cloud and the ground for a short time, is estimated to transfer around <u><em>15 coulombs</em></u> of charge !
The scenario in the question involves a "supercapacitor". 3 F is is no ordinary component ... One distributor I checked lists one of these that's able to stand 24 volts on it, but that product costs $35 apiece, you have to order at least 100 of them at a time, and they take 2 weeks to get.
Also, IF you can charge this animal to 24 volts, it will hold 864J of energy. You'd probably have a hard time accomplishing this task with a bag of leftover AA batteries.
Answer:
<h3>1.01 s</h3>
Explanation:
Using the equation of motion S = ut+1/2gt² to solve the problem where;
u is the initial velocity of the chocolate = 0m/s
t is the time taken
g is the acceleration due to gravity = 9.81m/s²
S is the height of fall = 5.0m
Substituting the given parameter into the formula to get the time t we have;
5 = 0(t)+1/2(9.81)t²
5 = 4.905t²
t² = 5/4.905
t² = 1.019
t = √1.019
t = 1.009 secs
<em>Hence it will take 1.01 secs for me to catch the chocolate bar</em>
