Complete question:
It is measured that 3/4 of a body's volume is submerged in oil of density 800kg/m³. What is the specific gravity of oil?
Answer:
The specific gravity of the oil is 0.8.
Explanation:
Given;
density of the oil, 
= 800 kg/m³
density of water, 
= 1000 kg/m³
The specific gravity of any substance is the ratio of the substance density to the density of water.
Specific gravity of the oil = density of the oil / density of water
Specific gravity of the oil = 800/1000
Specific gravity of the oil = 0.8
Therefore, the specific gravity of the oil is 0.8.
Answer: D) dedicate as many hours as needed to the work.
Explanation:
edge 2020
4.3A.
The easiest way to solve this problem is find the equivalent resistance for parallel resistor 1/Req = 1/R1 + 1/R2 + 1/R3 in the three-branch parallel network with branches whose resistance are 8Ω.
1/Req = 1/8 Ω + 1/8 Ω + 1/8 Ω
1/Req = 3/8 Ω
Req = 8/3 Ω = 2.667Ω
Req = 2.7Ω
So, the equivalent circuit will be the 20.0V battery in series with a resistor 2.0Ω and the equivalent resistor 2.7Ω.
Using Ohm's Law to find the current provide by the 20.0V voltage source:
V = I*R ------> I = V/R
I = 20.0V/(2.0Ω + 2.7Ω)
I = 20.0V/4.7Ω
I = 4.3A
