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3 years ago

12

why can you smell a cake baking when you are in your bedroom chemistry how does kinetic theory explain how you can smell coffee

and bacon at the same time?

1 answer:

Ymorist [56]3 years ago

4 0

Answer:

The smell from the cake leaves the room at high velocities because of diffusion.

Kinetic theory:

The kinetic theory applies to gases and describes their random movement and collisions in the whole volume that they are allowed to fill. This movement depends on factors like temperature and pressure.

Coffee and bacon particles will exist in the air in gaseous form. They will be colliding with each other, with all the other air particles and with the room walls to eventually disperse evenly in the whole room. They will be detected when coming into contact with olfactory receptors in the nose. They will reach the nose at the same temperature and there are equal amounts of particles of each.

You might be interested in

How many neutrons and protons (nucleons) does an atom with

mezya [45]

Answer:

E

Explanation:

None of the above

The atom with the symbol S is called sulphur Sulphur has atomic number 16 which means that it has 16 protons. Sulphur-32 has 32 nucleons - 16 protons and 16 neutrons.Sulfur is a chemical element It is nonmetallic. Under normal conditions, sulfur atoms form cyclic octatomic molecules with a chemical formula S8. Elemental sulfur is a bright yellow, crystalline solid at room temperature.

4 0

4 years ago

A frictionless piston cylinder device is subjected to 1.013 bar external pressure. The piston mass is 200 kg, it has an area of

Bad White [126]

Answer:

a) $T_{2} = 360.955\,K$ , $P_{2} = 138569.171\,Pa\,(1.386\,bar)$ , b) $T_{2} = 347.348\,K$ , $V_{2} = 0.14\,m^{3}$

Explanation:

a) The ideal gas is experimenting an isocoric process and the following relationship is used:

$\frac{T_{1}}{P_{1}} = \frac{T_{2}}{P_{2}}$

Final temperature is cleared from this expression:

$Q = n\cdot \bar c_{v}\cdot (T_{2}-T_{1})$

$T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{v}}$

The number of moles of the ideal gas is:

$n = \frac{P_{1}\cdot V_{1}}{R_{u}\cdot T_{1}}$

$n = \frac{\left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}} \right)\cdot (0.12\,m^{3})}{(8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K} )\cdot (298\,K)}$

$n = 5.541\,mol$

The final temperature is:

$T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (30.1\,\frac{J}{mol\cdot K} )}$

$T_{2} = 360.955\,K$

The final pressure is:

$P_{2} = \frac{T_{2}}{T_{1}}\cdot P_{1}$

$P_{2} = \frac{360.955\,K}{298\,K}\cdot \left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}}\right)$

$P_{2} = 138569.171\,Pa\,(1.386\,bar)$

b) The ideal gas is experimenting an isobaric process and the following relationship is used:

$\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}}$

Final temperature is cleared from this expression:

$Q = n\cdot \bar c_{p}\cdot (T_{2}-T_{1})$

$T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{p}}$

$T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (38.4\,\frac{J}{mol\cdot K} )}$

$T_{2} = 347.348\,K$

The final volume is:

$V_{2} = \frac{T_{2}}{T_{1}}\cdot V_{1}$

$V_{2} = \frac{347.348\,K}{298\,K}\cdot (0.12\,m^{3})$

$V_{2} = 0.14\,m^{3}$

4 0

4 years ago

when the volume of a gas is changed from 3.75 L to 6.52 L the temperature will change from 100k to blank k

Makovka662 [10]

Guy-Lussac's Law states that the volume and the temperature are directly proportional given that the pressure remains constant.

For this problem, we will assume constant pressure. Based on the law:
(Volume/Temperatur)1 = (Volume/Temperature)2
(3.75/100) = (6.52/T)
T = 166.667 kelvin

4 0

4 years ago

Read 2 more answers

Select the correct answer. What is the percent composition of silicon in silicon carbide (SiC)? A. 28% B. 50% C. 70% D. 142%

Nadya [2.5K]

Answer:

C. 70%

Explanation:

Atomic Mass of the silicon = 28 g.

Atomic mass of the Carbon = 12 g.

Total mass of the Silicon Carbide = 28 + 12

= 40 g.

Now, Using the formula.

% Composition = Mass of the silicon/Total mass of the compound × 100 %

= 28/40 × 100 %

= 70 %

Hence, % composition of the silicon in SiC is 70%

7 0

3 years ago

If two separate containers A and B have the same volume and temperature, but container A has more gaseous molecules than B, then

topjm [15]

Answer:

Higher pressure, is the right answer.

Explanation:

The A will have a higher pressure. Since we have given the volume and temperature is same in both containers A and B. Below is the calculation for proof that shows which container has the higher pressure while keeping the volume and temperature the same.

$So, \ V_A = V_B \\\frac{n_A T_A}{P_A} = \frac{n_B T_B}{P_B} \\Here, \ T_A = T_B \\P_A = \frac{n_A}{n_B} \times P_B \\\frac{n_A}{n_B} > 1 \\\frac{P_A}{P_B} > 1 \\P_A > P_B \\$

Therefore, the container “A” will have higher pressure.

8 0

3 years ago