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3 years ago

Describe the process you used to build a model. What did you do first? second?

Chemistry

1 answer:

dimaraw [331]3 years ago

3 0

First read the introduction.

Seconds look at the pictures how to build it.

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Question:

Nikolay [14]

Answer:

north pole, south pole, and magnetic field

Explanation:

the earth basically has a giant bar magnet inside it( the axis). Earth has a north pole, a south pole, and a magnetic field which are the same things that a bar magnet has.

4 0

3 years ago

Rolls of foil are 304 mmmm wide and 0.014 mmmm thick. (The density of foil is 2.7 g/cm3g/cm3 .) What maximum length of foil can

ratelena [41]

Answer:

92.2 m

Explanation:

Given that:=

The breadth = 304 mm

Height = 0.014 mm

Let Length = x mm

Volume = $Length\times breadth\times height$

Thus,

Volume = $304\times 0.014\times x\ mm^3=4.256x\ mm^3$

Also, 1 mm³ = 0.001 cm³

So, volume = 0.004256 cm³

Given that density = 2.7 g/cm³

Mass = 1.06 kg = 1060 g

So,

$Volume=\frac{Mass}{Density}=\frac{1060}{2.7}\ cm^3=392.59\ cm^3$

So,

0.004256*x = 392.59

x = 92243.89 mm

Length of foil = 92243.89 mm = 92.2 m

3 0

2 years ago

What does promoters in chemical reaction improve

dolphi86 [110]

Answer:

Promoter, in chemistry, substance added to a solid catalyst to improve its performance in a chemical reaction. By itself the promoter has little or no catalytic effect. Some promoters interact with active components of catalysts and thereby alter their chemical effect on the catalyzed substance.

Explanation:

7 0

2 years ago

What can help keep nitrate levels within the safe range?

Paha777 [63]

Answer: Drinking water with levels of nitrate at or below 10 mg/L is considered safe for everyone.

Explanation:

The U.S. Environmental Protection Agency (EPA) standard for nitrate in drinking water is 10 milligrams of nitrate (measured as nitrogen) per liter of drinking water (mg/L).

4 0

3 years ago

The equilibrium constant for the reaction of fluorine gas with bromine gas at 300 K is 54.7 and the reaction is: Br2(g) + F2(g)

alisha [4.7K]

Answer:

The correct answer is 0.024 M

Explanation:

First we use an ICE table:

Br₂(g) + F₂(g) ⇔ 2 BrF(g)

I 0.111 M 0.111 M 0

C -x -x 2 x

E 0.111 -x 0.111-x 2x

Then, we replace the concentrations of reactants and products in the Kc expression as follows:

Kc= $\frac{[BrF ]^{2} }{[ F_{2} ][Br_{2} ]}$

Kc= $\frac{(2x)^{2} }{(0.111-x)(0.111-x)}$

54.7= $\frac{4x^{2} }{(0.111-x)^{2} }$

We can take the square root of each side of the equation and we obtain:

7.395= $\frac{2x}{(0.111-x)}$

0.111(7.395) - 7.395x= 2x

0.82 - 7.395x= 2x

0.82= 2x + 7.395x

⇒ x= 0.087

From the x value we can obtain the concentrations in the equilibrium:

[F₂]= [Br₂]= 0.111 -x= 0.111 - 0.087= 0.024 M

[BrF]= 2x= 2 x (0.087)= 0.174 M

So, the concentration of fluorine (F₂) at equilibrium is 0.024 M.

8 0

3 years ago