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german
3 years ago
8

Describe the process you used to build a model. What did you do first? second?

Chemistry
1 answer:
dimaraw [331]3 years ago
3 0
First read the introduction.

Seconds look at the pictures how to build it.
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Why is it called alkaline battery?
Delicious77 [7]
Alkaline battery are a type of primary battery dependent upon the reaction between zinc metal and manganese dioxide.
The alkaline battery gets its name because it has an alkaline electrolyte of potassium hydroxide, instead of the acidic ammonium chloride or zinc chloride electrolyte of the zinc-carbon batteries.
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3 years ago
Please someone help me Balance this equation.
NeTakaya

Answer: This is an oxidation-reduction (redox) reaction:

3 C-II - 12 e- → 3 CII (oxidation)

4 CrVI + 12 e- → 4 CrIII (reduction)

C2H5OH is a reducing agent, K2Cr2O7 is an oxidizing agent.

7 0
2 years ago
What is the basis for the classification of changes in matter into physical and chemical changes quizlet
laiz [17]

Explanation:

The basis for classifying changes in matter into physical and chemical change is to see if a material is altered after going through a process.

In a physical change only the state of matter is usually altered especially its form or shape.

Chemical change alters a substance by producing new kinds that are totally different from it.

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6 0
3 years ago
The amount of energy needed to heat 6.2 g of a substance from 50.0°C to 80.0°C is 27.4 J. What is the specific heat capacity of
taurus [48]

Answer:

The heat capacity for the sample is 0.913 J/°C

Explanation:

This is the formula for heat capacity that help us to solve this:

Q / (Final T° - Initial T°) = c . m

where m is mass and c, the specific heat of the substance

27.4 J / (80°C - 50°C) = c . 6.2 g

[27.4 J / (80°C - 50°C)] / 6.2 g = c

27.4 J / 30°C . 1/6.2g = c

0.147 J/g°C = c

Therefore, the heat capacity is 0.913 J/°C

7 0
3 years ago
A red sports drink contains Red 40 dye. A 5.4 mL aliquot of this sports drink was diluted to 25.0 mL with deionized water in a v
miskamm [114]

Answer:

84.0 ppm is the concentration of Red 40 dy in the original sports drink.

Explanation:

Concentration of red dye in sport drink before dilution C_1=?

Volume of the sport drink before dilution V_1=5.4 mL

Concentration of red dye in sport drink after dilution C_2=18.1 ppm

Volume of the sport drink after dilution V_2=25.0 mL

C_1V_1=C_2V_2( dilution )

C_1=\frac{C_2V_2}{V_1}=\frac{18.1 ppm\times 25.0 mL}{5.4 mL}

C_1=83.80 ppm\approx 84.0ppm

84.0 ppm is the concentration of Red 40 dy in the original sports drink.

6 0
3 years ago
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