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3 years ago

The force of gravity on a car driving on the surface of a planet is called

Physics

2 answers:

nata0808 [166]3 years ago

8 0

The answer should be A) Mass.

Katena32 [7]3 years ago

4 0

C) Weight is correct. The force of gravity acting upon anything is weight.
A) mass is how much stuff is in something
B) relates to freefall, after the resistance in the air prevents any acceleration
D) freefall=object falling

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Basking in the sun, a 1.10 kg lizard lies on a flat rock tilted at an angle of 15.0° with respect to the horizontal. What is the

Ray Of Light [21]

10.4 N

Given

m = 1.10 kg

θ = 15.0°

g = 9.81 m/s2

Solution

Fnet, y = ΣF y = Fn − Fg, y = 0

Fn = Fg, y = Fg

cosθ = mgcosθ

Fn = (1.10 kg)(9.81 m/s2

)(cos15.0°) = 10.4 N

3 0

3 years ago

It is known that the gravitational force of attraction between two alpha particles is much weaker than the electrical repulsion.

natali 33 [55]

Answer:

The ratio of gravitational force to electrical force is 3.19 x 10^-36

Explanation:

mass of an alpha particle = 6.64 x $10^{-27}$ kg

charge on an alpha particle = +2e = +2(1.6 x $10^{-19}$ C) = 3.2 x $10^{-19}$ C

distance between particles = d

For gravitational attraction:

The force of gravitational attraction F = $\frac{Gm^{2} }{r^{2} }$

where G = gravitational constant = 6.67 x $10^{-11}$ m^3 kg^-1 s^-2

r = the distance between the particles = d

m = the mass of each particle

therefore, gravitational force = $\frac{6.67*10^{-11}*(6.64*10^{-27} )^{2} }{d^{2} }$ = $\frac{2.94*10^{-63} }{d^{2} }$ Newton

For electrical repulsion:

Electrical force between the particles = $\frac{-kQ^{2} }{r^{2} }$

where k is the Coulomb's constant = 9.0 x $10^{9}$ N•m^2/C^2

r = distance between the particles = d

Q = charge on each particle

therefore, electrical force = $\frac{-9*10^{9}*(3.2*10^{-19} )^{2} }{d^{2} }$ = $\frac{-9.216*10^{-28} }{d^{2} }$ Newton

the negative sign implies that there is a repulsion on the particles due to their like charges.

Ratio of the magnitude of gravitation to electrical force = $\frac{2.94*10^{-63} }{9.216*10^{-28} }$

==> 3.19 x 10^-36

8 0

3 years ago

A quantity of gas has a volume of 0.20 cubic meter and an absolute temperature of 333 degrees kelvin. When the temperature of th

Elena L [17]

P1v1/t1 = p2v2/t2

p1=p2, v1=.2, t1=333, t2=533
we can find v2 from this

be aware, temperature must be in Kelvin.

7 0

3 years ago

If a car changes ita velocity from 32km/hr to 54km/hr in 8.0 seconds, what is its acceleration

Andrews [41]

Firstly, let's convert the velocities in km/hr to m/s
32*1000/3600=8.89m/s
54*1000/3600=15m/s
From the formula, acceleration=V-U/t
15-8.89/8=0.76m/s²
hope this helps.

7 0

3 years ago

Can someone help me please

TEA [102]

Answer:

Explanation:

Because it is impossible for it to show the real depth of the ocean and how deep it is

8 0

3 years ago