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3 years ago

The force of gravity on a car driving on the surface of a planet is called

Physics

2 answers:

nata0808 [166]3 years ago

8 0

The answer should be A) Mass.

Katena32 [7]3 years ago

4 0

C) Weight is correct. The force of gravity acting upon anything is weight.
A) mass is how much stuff is in something
B) relates to freefall, after the resistance in the air prevents any acceleration
D) freefall=object falling

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What is hydroelectric power ? Answer quickly..!

GenaCL600 [577]

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Hydroelectric power, also called hydropower is the electricity produced from generators driven by turbines that convert the potential energy of falling or fast-flowing water into mechanical energy.

7 0

3 years ago

Read 2 more answers

1. Determine the image distance in each of the following.

miskamm [114]

It is given that for the convex lens,

Case 1.

u=−40cm

f=+15cm

Using lens formula

−

v=+24.3cm

The image in formed in this case at a distance of 24.3cm in left of lens.

Case 2.

A point source is placed in between the lens and the mirror at a distance of 40 cm from the lens i.e. the source is placed at the focus of mirror, then the rays after reflection becomes parallel for the lens such that

u=∞

f=15cm

Now, using mirror’s formula

∞

v=+15cm

The image is formed at a distance of 15cm in left of mirror

6 0

3 years ago

Help me plsssss help me plsssss

Zepler [3.9K]

Answer:

It is d. 0.80
Trust me i got it right took it and got it right

4 0

3 years ago

When a force of 450N pushes on a 20kg box as

ehidna [41]

Answer:

ma+mgsinh0+f=F∴(25)(0.75)+(25)(10)sinh0+μkN=F∴18.75+(250)(0.6h)+μk(mgcosh0=F⟹18.75+150+μk((25)(10)(0.76))=500∴168.75+μk(190)=500⟹μk(190)=331.25⟹μk=1.74

Explanation:

7 0

2 years ago

If an otherwise empty pressure cooker is filled with air of room temperature and then placed on a hot stove, what would be the m

Xelga [282]

Answer:

The magnitude of the net force F₁₂₀ on the lid when the air inside the cooker has been heated to 120 °C is $\frac{135.9}{A}N$

Explanation:

Here we have

Initial temperature of air T₁ = 20 °C = ‪293.15 K

Final temperature of air T₁ = 120 °C = 393.15 K

Initial pressure P₁ = 1 atm = ‪101325 Pa

Final pressure P₂ = Required

Area = A

Therefore we have for the pressure cooker, the volume is constant that is does not change

By Chales law

P₁/T₁ = P₂/T₂

P₂ = T₂×P₁/T₁ = 393.15 K× (‪101325 Pa/‪293.15 K) = ‭135,889.22 Pa

∴ P₂ = 135.88922 KPa = 135.9 kPa

Where Force = $\frac{Pressure}{Area}$ we have

Force = $F_{120}=\frac{135.9}{A}N$ .

4 0

3 years ago