Answer:
98N and 147N
Explanation:
We have the following information:

We can find the static fricton force as follow,

Where N is the normal force (mg)

Static friction force at 147N is greater than the force applied hence body does not move.

Explanation:
Bond Enthalpy : It is defined as amount of energy required to break a the particular bond in there gaseous state. It is also known as bond energy. It units are kJ/mol.
- Breaking of a bond is an Endothermic process (energy absorbed from the surroundings).
- Formation of bond is an Exothermic process (energy is released to the surroundings).
If the average bond enthalpy for a C-H bond is 413 kJ/mol, When the C-H bond breaks in which energy will be required ,which will be an endothermic reaction.
Answer:
KE = KE (incidental) - KE of emitted photons
or KE = h * f - Wf
So h * f = KE + Wf = 1.2 + 1.88 = 3.08 incident energy
If you double the frequency then h * f = 6.16
KE = 6.16 - 1.2 = 4.96 eV