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zalisa [80]
4 years ago
8

El coeficiente de variación de la resistencia con la temperatura del carbón es -0.0005/°c.Si la resistencia de una resistencia d

e carbón es de 1000 a0°c , determine su resistencia a 120°c
Physics
1 answer:
Doss [256]4 years ago
3 0

Answer:

 R (120) = 940Ω

Explanation:

The variation in resistance with temperature is linear in metals

           ΔR (T) = R₀ α ΔT

where α is the coefficient of variation of resistance with temperature, in this case α = -0,0005 / ºC

let's calculate

            ΔR = 1000 (-0,0005) (120-0)

            ΔR = -60 Ω

            ΔR = R (120) + R (0) = -60

            R (120) = -60 + R (0)

            R (120) = -60 + 1000

            R (120) = 940Ω

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3 years ago
Kisha is trying to determine if a cell is a plant or animal cell. She observes the cell under the microscope and describes some
Ann [662]
There are organelles in the plant cell that the animal cell does not have. Plant cells have rigid cell walls and animal cells have flexible cell membrane. Plant cells contains chloroplasts, which is something animal cells don't have. Also, large, liquid filled vacuoles can only be found in plant cells, and they can occupy up to 90% of a cell's volume. By looking at the cell and see if they have any of these characteristics determines if it is plant cell or animal cell.

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6 0
3 years ago
The law of conservation of energy states that (4 points)
slava [35]

Answer:

energy cannot be created or destroyed

Explanation:

Energy can't be created nor destroyed; rather, it transforms from one form to another.

8 0
3 years ago
A dog runs 300m North and sees the dog catcher and runs 120 m south .Whats the dogs displacement.The same jogger runs 3 miles ar
ozzi

Answer:

<em>1. 180 m</em>

<em>2. 1.5 miles/hour</em>

<em>3. 0 m/s </em>

Explanation:

The complete question is

A dog runs 300 m North and sees the dog catcher and runs 120 m south Whats the dogs displacement.

A jogger runs north for 3.0 miles. If this took 2.0 hours, what is the jogger’s average velocity in miles per hour?

The same jogger runs 3.0 miles on the track, starting and finishing his run after completing exactly 12 laps around the track. What is his average velocity?

1. Displacement is how far the dog moves from the original starting point.

If the dog runs 300 m north, and then 120 m south, then the displacement from the starting point will be

displacement = 300 - 120 = <em>180 m</em>

2. Displacement of the jogger = 3 miles

Time taken by the jogger = 2 hours

velocity of the jogger = ?

Velocity is = displacement/time

velocity = 3/2 = <em>1.5 miles/hour</em>

3. velocity = displacement/time

if the jogger completes exactly 12 laps around the track, then the jogger will return to the starting point. This means that the jogger's displacement from the starting point is 0 miles

Jogger's velocity will therefore be = <em>0 m/s </em>

8 0
3 years ago
A 9.0-kg bowling ball on a horizontal, frictionless surface experiences a net force of 6.0 n. what will be its acceleration?
Vladimir [108]

This question involves the concepts of Newton's Second Law of Motion.

The acceleration of the bowling ball will be "0.67 m/s²".

<h3>Newton's Second Law of Motion</h3>

According to Newton's Second Law of Motion, when an unbalanced force is applied on an object, it produces an acceleration in it, in the direction of the applied force. This acceleration is directly proportional to the force applied and inversely proportional to the mass of the object. Mathematically,

F=ma\\\\a=\frac{F}{m}

where,

  • a = acceleration = ?
  • F = Magnitude of the applied force = 6 N
  • m = Mass of the ball = 9 kg

Therefore,

a=\frac{6\ N}{9\ kg}

a = 0.67 m/s²

Learn more about Newton's Second Law of Motion here:

brainly.com/question/13447525

#SPJ1

7 0
3 years ago
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