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Brrunno [24]
3 years ago
15

Helppppppppppppppppppp me

Chemistry
1 answer:
masya89 [10]3 years ago
8 0
The answer is A.
A pure substance is pure, so it cannot be separated in most cases.
You might be interested in
The region in which an electron is likely to be found is known as a(n) ____________.
Zinaida [17]

Answer:

orbital

Explanation:

electrons are found in an orbital

3 0
3 years ago
Which molecule below has hydrogen bonding? Which molecule below has hydrogen bonding? H2 CH3CH2OH HCl CH4 all of the above
QveST [7]

Answer:

CH_3CH_2OH

Explanation:

Hydrogen bonding:-

Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.

Partially positive end of the hydrogen atom is attracted to partially negative end of these atoms which is present in another molecule. It is strong force of attraction between the molecules.

Thus, hydrogen must be linked to electronegative atom which is oxygen, fluorine and nitrogen which is in CH_3CH_2OH and thus, it will shown hydrogen bonding.

3 0
3 years ago
How many moles of CaCl2 are contained in 0.448 L of a 0.85 M CaCl2 solution?
kati45 [8]

Answer:

0.3808

Explanation:

number of moles,n=Conc.XVol.

hence 0.85X0.448

3 0
3 years ago
N2 + 3H2 = 2NH3
My name is Ann [436]
This is so basic bro u gotta first move
6 0
3 years ago
Calculate the mass of water produced when 42 g of propane, c3h8, is burned with 115 g of oxygen
gavmur [86]
The balanced combustion reaction of propane, C₃H₈, is

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

Molar mass of propane: 44 g/mol
Moles of propane = 42 g * (1 mol/44g) = 0.9545 mol propane

Molar mass of oxygen: 32 g/mol
Moles of oxygen = 115 g * (1 mol/32 g) = 3.594 mol oxygen

Moles of oxygen needed to completely react propane:
0.9545 mol propane * (5 mol O₂/1 mol propane) = 4.7725 mol oxygen

Since the available oxygen is only 3.594 moles and propane needs 4.7725 moles, that means oxygen is our limiting reactant. We base the amount of water produced here.

Molar mass of water: 18 g/mol
Mass of water produced = 3.594 mol O₂ * (4 mol H₂O/5 mol O₂) * (18 g/mol)
Mass of water produced = 258.768 grams
6 0
3 years ago
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