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Brrunno [24]
3 years ago
15

Helppppppppppppppppppp me

Chemistry
1 answer:
masya89 [10]3 years ago
8 0
The answer is A.
A pure substance is pure, so it cannot be separated in most cases.
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Anyone think they can help me with this one?
BARSIC [14]
To name this Alkyne, simply count from the direction that will give the lowest starting number to appear at the beginning of the carbon triple bond.

If you were to count from the top of the chain, the position of the carbon next to the triple bond would be 4. Yet if you count from the bottom chain going left to right and above the chain, the position of the carbon next to the triple bond would be 3.

Then identify the groups that are connected off the parent chain, here we have a methyl group on carbon 2.

Thus the name would be 2 - methyl - 3 - heptyne. I believe.
4 0
3 years ago
When 20.0 grams of an unknown compound are dissolved in 500. grams of benzene, the freezing point of the resulting solution is 3
Lelu [443]

Answer: 120g/mol

Explanation:

The first step we are to take is to calculate the freezing point depression of the solution.

ΔT(f) = freezing point of pure solvent - freezing point of solution

ΔT(f) = 5.48 - 3.77

ΔT(f) = 1.71°C

Next we are to calculate the molal concentration of the solution using freezing point depression

ΔT(f) = K(f) * m

m = ΔT(f)/K(f)

m = 1.71/5.12

m = 0.333 molal

Now, we calculate the molecular weight of the unknown...

m = 0.333 mol = 0.333 mol X per kg of benzene

moles of X = 0.333 mol of X per kg of benzene * 0.5kg of benzene

moles of X = 0.1665

molecular weight of X = 20g of X/0.1665

molecular weight of X = 120/mol

5 0
3 years ago
Hello I need help very bad!!!
Oksanka [162]

D. Cell membrane: surrounds a cell and allows substances to pass in and out

6 0
3 years ago
How many moles are in 109 grams of kf
lions [1.4K]

Answer:

Explanation:

Molar mass of KF= 39 + 19= 58g/mol

Mass of KF = 109g

Amount = mass/molar mass

Amount = 109/58

Amount = 1.9moles

4 0
3 years ago
The reaction between solid white phosphorous and oxygen produces solid tetraphosphorous decaoxide (P4010).
Alchen [17]

Answer:

oxygen is limiting reactant

Explanation:

Given data:

Mass of phosphorus = 25.0 g

Mass of oxygen = 50.0 g

What is limiting reactant ?

Solution:

Chemical equation:

P₄   +  5O₂       →      P₄O₁₀

Number of moles of P₄:

Number of moles = mass/molar mass

Number of moles = 25.0 g/ 123.89 g/mol

Number of moles = 0.20 mol

Number of moles of  O₂:

Number of moles = mass/molar mass

Number of moles = 50.0 g/ 32 g/mol

Number of moles = 1.56 mol

now we will compare the moles of reactants with product:

        P₄          :            P₄O₁₀

         1           :              1

      0.20       :          0.20

      O₂           :         P₄O₁₀

       5            :         1

     1.56         :        1/5×1.56 = 0.312 mol

Less number of moles of product are formed by the oxygen thus it will act as limiting reactant.

8 0
3 years ago
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