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Ksenya-84 [330]
3 years ago
8

I need some advice, I know like this is random, and I can not do this cuz issa place for questions about school work and stuff,

but like I'm desperate no one will give me an answer so here is my question: I like a boy in my 5th-period class, and I dont know how to approach him, how do I can I be his friend and get his (S)nap or number?
Chemistry
2 answers:
alina1380 [7]3 years ago
5 0

Answer:

well try talking to him first and being his friend. introduce yourself and try not to be too awkward or shy. can't reltate lol. after that if he really likes you, he'll initiate stuffs ^^

Explanation:

nadya68 [22]3 years ago
5 0

Answer:

just try to be hist friend, and be chill

Explanation:

You might be interested in
Reaction rate is expressed in terms of changes in the concentration of reactants and products. Write a balanced equation for the
KengaRu [80]

Answer : The balanced equations will be:

CH_4+2O_2\rightarrow 2H_2O+CO_2

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

Now we have to determine the balanced equations corresponding to the following rate expressions.

Rate=-\frac{d[CH_4]}{dt}=-\frac{1}{2}\frac{d[O_2]}{dt}=+\frac{1}{2}\frac{d[H_2O]}{dt}=+\frac{d[CO_2]}{dt}

The balanced equations will be:

CH_4+2O_2\rightarrow 2H_2O+CO_2

5 0
3 years ago
What are the gas laws? (Include Boyle's law, charles's law, gay lussac's law, an avogadro's law) Could someone please summarize
Rina8888 [55]

Answer:

Boyle's Law: When the pressure of a gas increases, the volume of the gas will decrease as long as the temperature and amount of gas are constant.

So basically pressure is inversely proportional to Volume, when one increases, the other decreases, vice versa.

Equation: P_{1} V_{1} = P_{2} V_{2}

Charles Law: When the temperature of a gas increases, the volume of a gas will also increase if the pressure and amount of gas are constant.

So basically Temperature and volume are directly proportional.

Equation: \frac{V_{1}}{T_{1}} = \frac{V_{2} }{T_{2} }

Gay Lussac's Law: When the temperature of a gas increases, the pressure of a gas also increases when volume and the amount of gas remain constant.

Basically, Temperature and Pressure are directly proportional.

Equation: \frac{P_{1}}{T_{1}} = \frac{P_{2} }{T_{2} }

Avogadro's Law: The most intuitive gas law. When you increase the amount of gas, the volume will also increase.

Meaning the moles (amount of gas) is directly proportional to volume.

Equation: \frac{V_{1} }{n_{1} } = \frac{V_{2} }{n_{2} } (n stands for moles)

There is a combined gas law and ideal gas law but those are just the gas laws mentioned above but combined together. These should be everything.

8 0
2 years ago
Read 2 more answers
Part A
Roman55 [17]

These are two questions and two answers

Question 1.

Answer:

  • <u>7.33 × 10 ⁻³ c</u>

Explanation:

<u>1) Data:</u>

a) m = 9.11 × 10⁻³¹ kg

b) λ =  3.31 × 10⁻¹⁰ m

c) c = 3.00 10⁸ m/s

d) s = ?

<u>2) Formula:</u>

The wavelength (λ), the speed (s), and the mass (m) of the particles are reltated by the Einstein-Planck's equation:

  • λ = h / (m.s)

  • h is Planck's constant: h= 6.626×10⁻³⁴J.s

<u>3) Solution:</u>

Solve for s:

  • s = h / (m.λ)

Substitute:

  • s = 6.626×10⁻³⁴J.s / ( 9.11 × 10⁻³¹ kg ×  3.31 × 10⁻¹⁰ m) = 2.20 × 10 ⁶ m/s

To express the speed relative to the speed of light, divide by c =  3.00 10⁸ m/s

  • s =  2.20 × 10 ⁶ m/s / 3.00 10⁸ m/s = 7.33 × 10 ⁻³

Answer: s = 7.33 × 10 ⁻³ c

Question 2.

Answer:

  • 2.06 × 10 ⁻³⁴ m.

Explanation:

<u>1) Data:</u>

a) m = 45.9 g (0.0459 kg)

b) s = 70.0 m/s

b) λ =  ?

<u>2) Formula:</u>

Macroscopic matter follows the same Einstein-Planck's equation, but the wavelength is so small that cannot be detected:

  • λ = h / (m.s)

  • h is Planck's constant: h= 6.626×10⁻³⁴J.s

<u>3) Solution:</u>

  • λ = h / (m.s)

Substitute:

  • λ =  6.626×10⁻³⁴J.s / ( 0.0459 kg ×  70.0 m/s) = 2.06 × 10 ⁻³⁴ m

As you see, that is tiny number and explains why the wave nature of the golf ball is undetectable.

Answer: 2.06 × 10 ⁻³⁴ m.  

5 0
3 years ago
How should the nutritionist explain why fats cannot be directly converted into carbohydrates?
lara [203]

Fats cannot be directly converted into carbohydrates during gluconeogenesis, glucose is created from oxaloacetate. However, oxaloacetate generated from fats occurs via the citric acid cycle. Because carbons from fats must enter the citric acid cycle as acetyl CoA first, fats can only indirectly become carbohydrates.

Option B

<u>Explanation:</u>

Gluconeogenesis is the process by which glucose is produced in body from non carbohydrate sources like fat, amino acids etc. This process involves the conversion of each and every product into oxaloacetate and then conversion of oxaloacetate into pyruvate and then the reverse process of Glycolysis is followed.

The concentration of oxaloacetate and ADP maintains the process. An increased amount of both of them supports the gluconeogenesis. But all products must undergo citric acid cycle to get converted into oxaloacetate. So fats are indirectly converted into glucose.

7 0
4 years ago
At 25.0∘C, the molar solubility of barium chromate in water is 1.10×10−5 M . Calculate the solubility in grams per liter.
Lunna [17]
Hey there!

Molar mass :
<span>
 ‎BaCrO</span>4 =  ‎253.319 g/mol

(g/L) = molar solubility * molar mass

(g/L) =  ( 1.10 x 10⁻⁵ ) * 253.319

=> 2.79x10⁻³ g/L
7 0
3 years ago
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