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Ksenya-84 [330]
3 years ago
8

I need some advice, I know like this is random, and I can not do this cuz issa place for questions about school work and stuff,

but like I'm desperate no one will give me an answer so here is my question: I like a boy in my 5th-period class, and I dont know how to approach him, how do I can I be his friend and get his (S)nap or number?
Chemistry
2 answers:
alina1380 [7]3 years ago
5 0

Answer:

well try talking to him first and being his friend. introduce yourself and try not to be too awkward or shy. can't reltate lol. after that if he really likes you, he'll initiate stuffs ^^

Explanation:

nadya68 [22]3 years ago
5 0

Answer:

just try to be hist friend, and be chill

Explanation:

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Ice is less dense than water because of which type of bond? metallic nonpolar covalent ionic hydrogen
cluponka [151]
Hydrogen bond. Is the answer.
3 0
3 years ago
Read 2 more answers
How many moles of Na2CO3 are in 100.0ml of a 2.0M solution?
Anna [14]

M = moles of solute / liters of solution

2.00 M = x / 10.0 L

x = 20.0 mol

Suppose the molarity was listed as 2.0 M (two sig figs). How to display the answer? Like this:

20. mol

6 0
3 years ago
9.710 x 10-8<br> grams of Chy are how many molecules?<br> Use Cl = 35.45 g/mole.
aliya0001 [1]

Answer:

26.42

Explanation:

6 0
2 years ago
If 650. grams of C6H12O6 (FW 180.16) reacts with 650. grams of O2 (FW 32.00) in cellular respiration: C6H12O6 6 O2 --&gt; 6 CO2
cestrela7 [59]

Answer:

O2 is limiting reactant

Explanation:

To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:

<em>Moles C6H12O6:</em>

650g * (1mol/180.16g) = 3.608 moles C6H12O6

<em>Moles O2:</em>

650g * (1mol/32g) = 20.31 moles O2

Now, for a complete reaction of 3.608 moles of C6H12O6 are required:

3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2

As there are just 20.31 moles of O2,

<h3>O2 is limiting reactant</h3>
4 0
3 years ago
Calculate the mass ratio of S to O in SO, and then calculate the mass ratio of S to O in SO2, given that the mass of S is approx
ziro4ka [17]

Explanation:

From the knowledge of law of multiple proportions,

mass ratio of S to O in SO:

mass of S : mass of O

= 32 : 16

= 32/16

= 2/1

mass ratio of S to O in SO2:

= mass of S : 2 × mass of O

= 32 : 2 × 16

= 32/32

= 1/1

ratio of mass ratio of S to O in SO to mass ratio of S to O in SO2:

= 2/1 ÷ 1/1

= 2

Thus, the S to O mass ratio in SO is twice the S to O mass ratio in SO2.

8 0
3 years ago
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