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3 years ago

Mummification frequently preserves fine detail and internal organs true or false

Chemistry

1 answer:

mariarad [96]3 years ago

6 0

I believe thats false. think about the mummys youve seen? do you see fine detail and intact organs

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How many moles are in 400 ml of hydrogen

Nezavi [6.7K]

Answer:

403.176

Explanation:

I hope that the right answer.

8 0

4 years ago

Separating fluids, such as blood, is best accomplished using:

Vera_Pavlovna [14]

Centrifugation is usually use to separate different components of blood.

4 0

3 years ago

C(s)+H2(g)-> C2H6(g)

disa [49]

Explanation:

2 C(s) + 3 H2(g) = C2H6(g)

5 0

3 years ago

A chemist needs 1.25 moles of sugar to dissolve in 1 liter of water how many grams of sugar needed

sdas [7]

Answer:

The mass of sugar used is 427.5 grams.

Explanation:

The formula of common sugar is $\mathrm{C_{12}H_{22}O_{11}}$ .

Its molar mass of molecule is 342 grams per mole.

The number of moles of sugar used is equal to '1.25'

$\mathbf{Mole=\frac{Mass \ given \ in \ grams}{Molar \ mass \ of \ molecule \ in \ grams}}$

$\textrm{Mass in grams}=\textrm{Mole} \times \textrm{Molar mass of molecule in grams}$

$\textrm{Mass in grams}= 1.25\times342$

$\mathbf{Mass \ in \ grams=427.5 g}$

(NOTE : You can calculate molar mass by adding the mass of all the atoms present in the atom.

Mass of Oxygen (O) = 16 ; Total number of Oxygen atoms present = 11

Mass of Hydrogen (H) =1 ; Total number of Hydrogen Atoms present = 22

Mass of Carbon (C) = 12 ; Total number of Carbon atoms present = 12

Total mass of molecule = 12 × 12 + 1 × 22 + 16 × 11 = 342)

4 0

3 years ago

The activation energy for the reaction NO2 (g )+ CO (g) ⟶ NO (g) + CO2 (g) is Ea = 218 kJ/mol and the change in enthalpy for the

madreJ [45]

Answer:

$470\frac{KJ}{mol}$

Explanation:

The activation energy represents the energy barrier that reagents must pass to transform into products (or products to transform into reagents in a reverse reaction)

For any reaction, the change in enthalpy is related to the activation energy by the equation

$\Delta H =E_{a\ direct}-E_{a\ reverse}$

So, the activation energy for the reverse reaction is

$E_{a\ reverse}=E_{a\ direct}-\Delta H =218 \frac{KJ}{mol} - (-252)\frac{KJ}{mol}=470\frac{KJ}{mol}$

4 0

3 years ago