Answer:
The magnitude of the maximum radial acceleration of the stone is 122.034 m/s^2
Explanation:
Maximum radial acceleration (a) = w^2r
w = v/r
w^2 = (v/r)^2 = v^2/r^2
a = v^2/r^2 × r = v^2/r
v is the maximum speed the stone attains = 12 m/s
r is the radius of the circular path = 1.18 m
a = 12^2/1.18 = 144/1.18 = 122.034 m/s^2
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Answer:
Option C
Explanation:
The spring undergoes periodic motion. From Newton's first law, a body keeps moving until an unbalanced external force acts on it. So, the spring would continue to vibrate regularly and in repeated fashion. In the absence of any dampening force, the spring continues to oscillate.
Thus, option C is correct.
Answer:
t = 1
Explanation:
you dont know the value of the variable
Answer: a= 4.4ms-2
Displacement= 26.95 m
Explanation:
First, the speed in km/hr must be converted to m/s so that we can apply it in solving the question. The motion started from rest hence the initial velocity is 0m/s. The average displacement is also obtained from the equations of motion as shown in the image attached.