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agasfer [191]
4 years ago
8

What is the difference between diatomic and poly-atomic molecules? Site some examples.

Physics
1 answer:
Olegator [25]4 years ago
8 0
Their difference lies in the prefix used before each root word, atom. The diatomic molecules are composed only of 2 atoms such as that of the diatomic elements: H2, O2, N2, Cl2, etc. On the other hand, polyatomic molecules are made up of three or mole atoms such as NH4+, H2SO4, etc. 
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A hydraulic system contains 3 pistons. The input piston has an area of 0.625 in2, one of the output pistons ( piston A ) has an
Xelga [282]

The area of Piston A is 13.88 in^2

What is a hydraulic system?

The hydraulic system functions by using pressurized fluid.  The power of liquid fuel in hydraulics is significant and as a result, they are commonly used in heavy equipment.

Hydraulic system simply means a mechanical function that operates through the force of liquid pressure.

Here

A hydraulic system contains 3 pistons.

Pressure, P = 1440 psi

for piston A:

Area, A= 0.625 in^2

Force, F = 20,000 lb

We know that,

Force = Pressure x Area

F = P x A

Area ( piston A) = F / P

A = 20,000 / 1440

A = 13.88 in^2

Hence,

The area of Piston A is 13.88 in^2

Learn more about hydraulic system here:

<u>brainly.com/question/27961071</u>

#SPJ4

4 0
2 years ago
Which is the best estimate for the mass of a typical lineman on a high school football team
fgiga [73]

We have that the best estimate for the mass of a typical lineman on a high school football team is

100,000 g=100kg

From the options

1. 100,000 g

2. 100,000 kg

3. 100,000 mg

Generally

A Typical lineman cannot be as small as

100000mg=0.1kg=100g

A Typical linesman cannot be as massive as

100,000kg as that is unrealistic

With the Average Mass of A Typical linesman can be

100,000 g=100kg

In conclusion

The best estimate for the mass of a typical lineman on a high school football team is

100,000 g=100kg

For more information on this visit

brainly.com/question/10069252

7 0
3 years ago
A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through
Neporo4naja [7]

Answer:

Explanation:

Let the charge on proton be q .

energy gain by proton in a field having potential difference of V₀

= V₀ q

Due to gain of energy , its kinetic energy becomes 1/2 m v₀²

where m is mass and v₀ is velocity of proton

V₀ q = 1/2 m v₀²

In the second case , gain of energy in electrical field

= 2 V₀q , if v be the velocity gained in the second case

2 V₀q = 1/2 m v²

1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²

mv² = 2  m v₀²

v = √2 v₀

6 0
3 years ago
Which is an example of transforming potential energy to kinetic energy? Select two options
blsea [12.9K]

<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u> </u><u>:</u><u> </u>

<em><u>.</u></em><em><u>changing chemical energy to thermal energy</u></em>

<em><u>.</u></em><em><u>changing nuclear energy to radiant energy</u></em>

<u>E</u><u>x</u><u>p</u><u>l</u><u>a</u><u>n</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>:</u><u> </u>

<h3><em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>t</u></em><em><u> </u></em><em><u>h</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em><em><u>s</u></em><em><u> </u></em><em><u>y</u></em><em><u>o</u></em><em><u>u</u></em><em><u> </u></em><em><u>m</u></em><em><u>a</u></em><em><u>t</u></em><em><u>e</u></em><em><u> </u></em><em><u>)</u></em><em><u>)</u></em></h3>
3 0
3 years ago
During a race, a runner runs at a speed of 6 m/s. Four seconds later, she is running at a speed of 14 m/s. What is the runner's
DedPeter [7]

Answer:

D. 2 m/s²

Step-by-step explanation:

Initial speed of the runner (u) = 6 m/s

Final speed of the runner (v) = 14 m/s

Time taken (t) = 4 s

By using equation of motion, we get:

\bf \longrightarrow v = u + at \\  \\  \rm \longrightarrow 14 = 6 + 4a \\  \\  \rm \longrightarrow 14 - 6 = 6 - 6 + 4a \\  \\  \rm \longrightarrow 8 = 4a \\  \\  \rm \longrightarrow 4a = 8 \\  \\  \rm \longrightarrow  \dfrac{4a}{4}  =  \dfrac{8}{4}  \\  \\  \rm \longrightarrow a = 2 \: m {s}^{ - 2}

\therefore Acceleration of the runner (a) = 2 m/s²

3 0
3 years ago
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