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pishuonlain [190]
3 years ago
10

Any motion that is regular and repeating is referred to as a periodic motion. Most objects that vibrate do so in a regular and r

epeated fashion much like this spring seen here. According to Newton's 1st Law of Motion,
A) the greater the mass of the spring, the greater the periodic motion.
B) the lower the mass of the spring, the faster the repeating motion occurs.
C) the periodic motion will continue forces acting on the spring are unbalanced.
D) there is an equal and opposite reaction force that slows down the periodic motion.
Physics
2 answers:
disa [49]3 years ago
7 0

Answer:

C.

Explanation: I took the test and it was correct.

vladimir2022 [97]3 years ago
6 0

Answer:

Option C

Explanation:

The spring undergoes periodic motion. From Newton's first law, a body keeps moving until an unbalanced external force acts on it. So, the spring would continue to vibrate regularly and in repeated fashion. In the absence of any dampening force, the spring continues to oscillate.

Thus, option C is correct.

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A car is traveling at 20 meters/second and is brought to rest by applying brakes over a period of 4 seconds what is its average
Fofino [41]
Avg. acceleration = -5 m/s^2.
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Did the bird population appear to benefit from the elimination of the rattlesnakes
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Yes because there's less rattlesnakes to eat them

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7 0
4 years ago
If the world population grows at a constant rate of 1.8% per annum, how many years will it take to double? A) 17.7 years
AleksandrR [38]

Answer:

after 38.8 years it will double

correct option is D 38.8 years

Explanation:

given data

population grows rate = 1.8%

to find out

how many years will it take to double

solution

we consider here initial population is x

so after 1 year population will be = (100% + 1.8% ) x = 1.018 x

and after n year population will be = 1.018^{n} x

so it will double

2x = 1.018^{n} x

take log both side

log 2 = n log (1.018)

n = \frac{log2}{log1.018}

n = 38.853

so after 38.8 years it will double

correct option is D 38.8 years

4 0
3 years ago
How long does it take to raise the temperature of the air in a good-sized living room (3.00m×5.00m×8.00m) by 10.0∘C? Note that t
tekilochka [14]

Answer : The time required is, 16.1 minutes.

Explanation :

First we have to calculate the amount of heat required to increase the temperature is:

Q=mC\Delta T\\\\Q=\rho VC\Delta T

(m=\rho V)

where,

Q = amount of heat required = ?

m = mass

\rho = density of air = 1.20kg/m^3

V = volume of air

C = specific heat of air = 1006J/kg^oC

\Delta T = change in temperature = 10.0^oC

Now put all the given values in above formula, we get:

Q=\rho VC\Delta T

Q=(1.20kg/m^3)\times (3.00m\times 5.00m\times 8.00m)\times (1006J/kg^oC)\times (10.0^oC)

Q=1.449\times 10^6J

Now we have to calculate the time required.

Formula used :

t=\frac{Q}{P}

where,

t = time required = ?

Q = amount of heat required = 1.449\times 10^6J

P = power = 1500 W

Now put all the given values in above formula, we get:

t=\frac{1.449\times 10^6J}{1500W}

t=966s\times \frac{1min}{60s}=16.1min

Thus, the time required is, 16.1 minutes.

5 0
3 years ago
All objects emit what radiation
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If an object is not at Absolute Zero, then it is
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