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AlekseyPX
3 years ago
15

7 plus what equals 23

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
8 0
The answer 16 will be what you are looking for.

Kobotan [32]3 years ago
6 0
7+16= 23. Hope that helps.
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(Please help, problem is in the photo.)
Rama09 [41]
First we need to find the gradient of K
which is y1-y2/x1-x2
(-1,3) and (5,-2)
so it becomes 3-(-2)/-1-5
m=-5/6
when two lines are perpendicular their gradients multiply to make -1
that means the gradient of L has to be 6/5
we can substitute the point on L (5,-2) and the gradient of 6/5 into y=mx+c
-2 = (6/5) x 5 + c
c = -8
the equation of line L is y= 6x/5 -8
6 0
3 years ago
Read 2 more answers
Please help me answer this
vodka [1.7K]

Answer:


Step-by-step explanation:


8 0
3 years ago
How do I do the bus stop method?
hichkok12 [17]
The bus stop method is just like division.
Ex
137÷5= 
1.) 5 goes into one zero times so there is a zero on top.
2.) 5 goes into 13 two times, so after the zero there is a 2.
3.) 5 goes into 37 seven times so there is a 7 after the 2.
4.) There is a 2 left and five can't go into school therefore that is a remainder.

    027R2
5/137
  <u>- 10</u>
     37
   <u>-35</u>
       2
Hoped I helped:D

6 0
4 years ago
HELP PLZ DUE RN BRAINIEST TO WHOEVER RIGHT
Y_Kistochka [10]

Answer:

x = \dfrac{2}{5} + \dfrac{\sqrt{14}}{5}   or   x = \dfrac{2}{5} - \dfrac{\sqrt{14}}{5}

Step-by-step explanation:

5x^2 - 2 = 4x

5x^2 - 4x - 2 = 0

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

x = \dfrac{-(-4) \pm \sqrt{(-4)^2 - 4(5)(-2)}}{2(5)}

x = \dfrac{4 \pm \sqrt{16 + 40}}{10}

x = \dfrac{4 \pm 2\sqrt{14}}{10}

x = \dfrac{2 \pm \sqrt{14}}{5}

x = \dfrac{2}{5} + \dfrac{\sqrt{14}}{5}   or   x = \dfrac{2}{5} - \dfrac{\sqrt{14}}{5}

4 0
3 years ago
Read 2 more answers
Divide. (6x³ + 2x² + 3x −4) ÷ (x² + 3x +4)​
Aloiza [94]

6x³ + 2x² + 3x - 4 is not exactly divisible by x² + 3x - 4.

Given,

The expression : 6x³ + 2x² + 3x - 4

We have to divide the given expression by x² + 3x - 4.

Let's take 6x³ + 2x² + 3x - 4 as p(x) and x² + 3x - 4 as g(x).

If p(x) is divisible by the factors of g(x), then p(x) is divisible by g(x).

So, let's factorize  x² + 3x - 4

x² + 3x - 4 = (x - 1) (x + 4)

Now,

p(x) = 6x³ + 2x² + 3x - 4

By using remainder theorem,

If p(1) = 0 and p(4) = 0, then p(x) is divisible by g(x).

So,

p(1) = 6 × 1³ + 2 x 1² + 3 x 1 -4

p(1) = 6 + 2 + 3 - 4

p(1) = 11 - 4

p(1) = 7

Next,

p(4) = 6 x 4³ + 2 x 4² + 3 x 4 - 4

p(4) = 6 x 64 + 2 x 16 + 12 - 4

p(4) = 384 + 32 + 12 - 4

p(4) = 424

Here, p(1) and p(4) is not 0.

So, p(x) is not divisible by g(x).

That is, 6x³ + 2x² + 3x - 4 is not exactly divisible by x² + 3x - 4.

Learn more about divisibility here:

brainly.com/question/1591815

#SPJ1

8 0
1 year ago
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