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ololo11 [35]
3 years ago
6

While it’s impossible to design a perpetual motion machine, that is, a machine that keeps moving forever, come up with ways to k

eep some type of periodic motion going for a very long time. Explain the limits on perpetual motion. Discuss what slows down a machine and how you might minimize those effects for at least one specific form of periodic motion, such as the motion of a spring or pendulum, or circular motion. Come up with an inventive solution!
Physics
2 answers:
svetlana [45]3 years ago
5 0

Answer:

Explanation:

It would be hard so many factors play a role in this angle kinetic potential energy gravity positioning height weight etc.to keep something as described moving as long as possible you'd have to build it heavily enough to balance out the momentum at each climax of the swing to balance with the gravitational pull of the earth core.I'd use a material such as copper for the variable.Also the weight distribution on the variables base plays a role.Take all the into account and experiment for a while!maybe one day you could find the right proportions in every role for kinetic potential gravitational momentum and weight to keep it going forever.

TEA [102]3 years ago
3 0
It would be hard so many factors play a role in this angle kinetic potential energy gravity positioning height weight etc.to keep something as described moving as long as possible you'd have to build it heavily enough to balance out the momentum at each climax of the swing to balance with the gravitational pull of the earth core.I'd use a material such as copper for the variable.Also the weight distribution on the variables base plays a role.Take all the into account and experiment for a while!maybe one day you could find the right proportions in every role for kinetic potential gravitational momentum and weight to keep it going forever. As said alotta factors play a huge role in this experiment  <span />
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If there is an object in top of another object, why does the upper object exert a downward normal force?​
rusak2 [61]

Answer:

This is because normal force is exerted perpendicularly to the point of contact between the upper and lower objects.  

Explanation:

This is because the upper object is still subject to gravitational pull. Therefore, the amount of force it exerts on the lower object due to gravity will be equal to the normal force that acts in the negative direction of gravitational force. Additionally, normal force is evident because the upper object will not go into the lower object.

4 0
3 years ago
A mercury manometer is connected on one side to a bulb containing argon, while the other end is open to atmospheric pressure, wh
belka [17]

Answer:

740, mm of Hg

Explanation:

The pressure of argon , in mm of Hg = difference in the level of mercury on either side of the manometer.

mercury column  in the open end of the manometer is 22 mm below that in the side connected to the argon and 762 mmHg,  end is open to atmospheric pressure.

therefore, The pressure of argon , in mm of Hg  =762 -22 = 740, mm of Hg

4 0
3 years ago
Using Kepler's 3rd law and Newton's law of universal gravitation, find the period of revolution P of the planet as it moves arou
weeeeeb [17]

Answer:

P =  \pi \sqrt{\frac{(R_1+R_2)^3}{2 \ GMS}}

Explanation:

From the attached diagram below:

AC = a (1 + e) = R₂     -------- equation (1)

CD = a ( 1 - e) = R₁     ---------   equation (2)

⇒ 1 - e = \frac{R_1}{a}

e= 1 - \frac{R_1}{a}

Replacing the value for e into equation (1)

a(1+1- \frac{R_1}{a})= R_2

= 2a - R_1 = R_2

a= \frac{R_1+R_2}{2}

From Kepler's third law;

P = 2 \pi \sqrt{\frac{a^3}{GMS}}

P = 2 \pi \sqrt{\frac{(R_1+R_2)^3}{8GMS}}

P =  \pi \sqrt{\frac{(R_1+R_2)^3}{2 \ GMS}}

5 0
3 years ago
Number of atoms present in 1 mole of oxygen atom
Afina-wow [57]

Answer:

1 mole of every substance has 6.022 × 10^23 particles. This is called Avagadro's constant

3 0
4 years ago
An 800-N man stands at rest on two bathroom scales so that his weight is distributed evenly over both scales. The reading on eac
Olenka [21]

400 N

The weight of the man is evenly distributed on each scale

5 0
4 years ago
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