The scheme is shown below, the steps involved are as follow,
Step one: Reduction: The carbonyl group of given compound on reduction using
Wolf Kishner reagent converts the carbonyl group into -CH₂- group.
Step two: Epoxidation: The double bond present in starting compound when treated with
m-CPBA (<span>meta-Chloroperoxybenzoic acid) gives corrsponding epoxide.
Step three: Reduction: The epoxide is reduced to alcohol on treatment with
Lithium Aluminium Hydride (LiAlH</span>₄)<span> followed by hydrolysis.
Step four: Oxidation: The hydroxyl group (alcohol) is
oxidized to carbonyl (ketonic group) using oxidizing agent
Chromic acid (H</span>₂CrO₄).
Just post the question on here
The complete balanced chemical reaction is written as:
AgNO3 + KCl ---> AgCl
+ KNO3
where AgCl is our
precipitate
So calculating for moles
of AgCl produced: MM AgCl = 143.5 g/mol
moles AgCl = 0.326 g /
(143.5 g/mol) = 2.27 x 10^-3 mol
we see that there is 1
mole of Ag per 1 mole of AgCl so:
moles Ag = 2.27 x 10^-3
mol
The molarity is simply
the ratio of number of moles over volume in Liters, therefore:
Molarity = 2.27 x 10^-3
mol / 0.0977 L
<span>Molarity = 0.0233 M</span>
Right answer is B . Trust me .
apparently colorless light, for example ordinary daylight. It contains all the wavelengths of the visible spectrum at equal intensity.