Answer:
The answer to your question is Abundance N-14 = 99.63%
Abundance N-15 = 0.37%
Explanation:
Data
Average atomic mass = 14.0067 amu
N-14 = 14.003074002
N-15 = 15.00010897
Abundance N-14 = ? x
Abundance N-15 = ? 1 - x
Formula
Average atomic mass = (mass of N-14)x + (mass of N-15)(1 - x)
Substitution
14.0067 = 14.003074002x + 15.00010897(1 - x)
Solve for x
14.0067 = 14.003074002x + 15.00010897 - 15.00010897x
14.0067 - 15.00010897 = 14.003074002x - 15.00010897x
-0.9934 = -0.99703x
x = -0.9934 / -0.99703
x = 0.9963
Conclusion
Abundance N-14 = 0.9963 x 100 = 99.63 %
Abundance N-15 = 1 - 0.9963 = 0.0037 x 100 = 0.37 %
Answer:
188
Explanation:
For every 2 molecules of methanol reacted, 4 molecules of water are formed. Use this relationship to solve.
2/4 = 94/x
2x = 376
x = 188
188 molecules of water will be formed.
Answer:
youre right i think its 1 and 5
because it cant be 2 or 3
Explanation:
I hope this answers your question(s). Have a good weekend!
KE = mv²/2
m=2*KE/v²
v=50 m/s
KE=500J
m=2*KE/v² =2*500/50²=1000/2500= 0.4 kg
