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Agata [3.3K]
2 years ago
10

State two differences between physical change and chemical change

Chemistry
2 answers:
Lubov Fominskaja [6]2 years ago
6 0

Answer:

See explanation

Explanation:

1) Physical change is usually reversible, while chemical change isn't

2) Chemical change involves the change of chemical composition of matter while physical change doesn't

katovenus [111]2 years ago
6 0

Answer:

1. Physical changes only change the physical attributes of a substance, such as color or state, while chemical changes affect chemical composition.

2. In physical changes, no new energy or substances are produced.

Explanation:

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1. The heat of fusion for the ice-water phase transition is 335 kJ/kg at 0°C and 1 bar. The density of water is 1000 kg/m3 at th
vodomira [7]

Answer:

Expression for the change of melting temperature with pressure..> T₂ = T₁exp(-(P₂-P₁)/(3.61x10⁹ Pa), Freezing Point = 0°C

Explanation:

Derivation from state postulate

Using the state postulate, take the specific entropy,  , for a homogeneous substance to be a function of specific volume  and temperature  .

ds = (partial s/partial v)(t) dv + (partial s/partial T)(v) dT

During a phase change, the temperature is constant, so

ds = (partial s/partial v)(T)  dv

Using the appropriate Maxwell relation gives

ds = (partial P/partial T)(v) dv

s(β) – s(aplαha) = dP/dT (v(β) – v(α))

dP/dT = s(β) – s(α)/v(β) – v(α) = Δs/Δv

Here Δs and Δv are respectively the change in specific entropy and specific volume from the initial phase α to the final phase β.

For a closed system undergoing an internally reversible process, the first law is

du = δq – δw = Tds - Pdv

Using the definition of specific enthalpy, h and the fact that the temperature and pressure are constant, we have

du + Pdv = dh Tds,

ds = dh/T,

Δs = Δh/T = L/T

After substitution of this result into the derivative of the pressure, one finds

dp/dT = L/TΔv

<u>This last equation is the Clapeyron equation.</u>

a)

(dP/dT) = dH/TdV => dP/dlnT = dH/dV

=> dP/dlnT = dH/dV = [H(liquid) - H(solid)]/[V(liquid) - V(solid)]

= [335,000 J/kg]/[1000⁻¹ - 915⁻¹ m³/kg]

= -3.61x10⁹ J/m³ = -3.61x10⁹ Pa

=> P₂ = P₁ - 3.61x10⁹ ln(T₂/T₁) Pa

or

T₂ = T₁exp(-(P₂-P₁)/(3.61x10⁹ Pa)

b) if the pressure in Denver is 84.6 kPa:

T₂(freezing) = 273.15exp[-(84,600-100,000)/(3.61x10⁹)]

≅ 273.15 = 0°C T₁(freezing) essentially no change

5 0
3 years ago
Which part of a feedback mechanism causes change to make up for the departure from the set point? A. sensor B. effector C. respo
koban [17]
I would have to say C. Response.
5 0
3 years ago
Read 2 more answers
How much heat energy is required to raise the temperature of 15g of silver from 25°C to 55°C, assuming the specific heat of silv
Alenkasestr [34]

Answer:

108 j

Explanation:

.24 j/g-C  * 15 g * (55-25) =

6 0
2 years ago
Calculate the oxidation numbers of the elements in this equation<br> 2 Al2O3 → 4 Al + 3 O2
riadik2000 [5.3K]

Explanation:

Answer

Open in answr app

The rule used here is that the algebraic sum of the oxidation numbers of all the atoms a molecule is zero.

Al2O32× ( oxidation number of Al)+3× ( Oxidation number of O )  = 0

2× ( Oxidation number of Al) +3(−2)=0

2× ( oxidation number of Al) +6

∴ Oxidation number of Al =+3

5 0
3 years ago
Write a word equation for 2ZnS(s)+3O2(g) -&gt; 2ZnS(s) + 2SO3(g)
hjlf

2ZnS(s)+3O2(g) -> 2Zns(s) + 2SO3(g)

the above given equation is unbalanced as it contains 4 moles of sulphur in the output but in the input there are only two aoms of sulphur so to balance the equation we will write the equation as given under

balanced equation is

2ZnS(s)+3O2(g) -> 2Zn(s) + 2SO3(g)


In words:

When 2 moles of solid zinc sulfide reacts with 3 moles of oxygen gas gives 2 moles of solid zinc  and 2 moles of sulphur trioxide gas.

3 0
2 years ago
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