The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L
<h3>Balanced equation</h3>
2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)
From the balanced equation above,
4 moles of CO₂ were produced by 2 moles of C₂H₂
<h3>How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂</h3>
From the balanced equation above,
4 moles of CO₂ were produced by 2 moles of C₂H₂
Therefore,
12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂
<h3>How to determine the volume (in L) of C₂H₂ needed at STP</h3>
At standard temperature and pressure (STP),
1 mole of C₂H₂ = 22.4 L
Therefore,
6 moles of C₂H₂ = 6 × 22.4
6 moles of C₂H₂ = 134.4 L
Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L
Learn more about stoichiometry:
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Use the universal gas formula
PV=nRT
where
P=pressure ( 0.980 atm)
V=volume (L)
T=temperature ( 23 ° C = 23+273.15 = 296.15 ° K)
n=number of moles of ideal gas (0.485 mol)
R=universal gas constant = <span>0.08205 L atm / (mol·K)
Substitute values,
Volume, V (in litres)
=nRT/P
=0.485*0.08205*296.15/0.980
= 12.0256 L
= 12.0 L (to three significant figures)
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Answer:
It's False
Explanation:
In a chemical reaction, reactants that are not used up when the reaction is finished are called excess reagents. The reagent that is completely used up or reacted is called the limiting reagent, because its quantity limits the amount of products formed.
Hope this helps you
Explanation:
(Ques- A) Why does the first method for determining volume work only for a regular-shaped object?
<u>(Ans- A)</u> <em>Because the method requires precise dimensions of objects for result, which is not possible for irregular shaped objects.</em>
(Ques - B) Will the second method for determining volume work for any object or just an odd-shaped one? Why?
<u>(Ans-B)</u> <em>It will work for both regular and irregular shaped objects since both displace equal volumes of water.</em>
(Ques - C) Is one method of measurement more accurate than the other? Why or why not?
<u>(Ans-C)</u> <em>Both are pretty accurate, with some experimental errors which may creep in accidentally. </em>
(Ques- D) Would the displacement method of measurement work for a cube of sugar? What about a cork? Why?
<u>(Ans - D)</u> <em>No, the method would not work because sugar being soluble, will dissolve in water. </em>
<em>No, the method would not work because sugar being soluble, will dissolve in water. Cork is less dense than water so floats on it, with only part of it submerged in water, resulting in displacement of less volume of water than actual volume of Cork.</em>
(Ques-E) What did you find out from this investigation? Be thoughtful in your answer.
<u>(Ans- E)</u> <em>I learnt about determining volume of different objects from this investigation. </em>(Sorry, I know its not a very thoughtful answer)
