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Ede4ka [16]
3 years ago
14

A gaseous hydrogen and carbon containing compound is decomposed and found to contain 82.66% carbon and 17.34% hydrogen by mass.

The mass of 158 mL of the gas, measured at 556 mmHg and 25 ∘C, was found to be 0.275 g. What is the molecular formula of the compound?
Chemistry
1 answer:
Doss [256]3 years ago
3 0
For the answer to the question above, I'll show the solution to my answers

moles C = 82.66 g/ 12.0111 g/mol=6.882 
<span>moles H = 17.34 g/ 1.008 g/mol=17.20 </span>

<span>17.20/ 6.882 =2.5 => H </span>
<span>6.882 / 6.882 = 1 => C </span>

<span>to get whole numbers multiply by 2 </span>
<span>C2H5 ( empirical formula Molar mass = 29.062 g/mol) </span>

<span>n = pV/RT = 0.732 x 0.158 L/ 0.08206 x 298 K= 0.00473 </span>
<span>molar mass = 0.275/ 0.00473 =58.1 g/mol </span>

<span>58.1 / 29.062 = 2 </span>

<span>multiply by two the empirical formula </span>

<span>C4H10</span>
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Non metals whose 2 forms<br> 1]very hard <br> 2] conductor of electricity
Usimov [2.4K]

Answer:

Diamond

Explanation:

Diamond has covalent bonds, which makes it a non-metal.

However, it also has a tetrahedral structure, which holds its C atoms together by strong forces, thus making it hard.

Diamond also has free-moving electrons due to its tetrahedral structure, thus making it possible to conduct electricity.

3 0
2 years ago
Due to the small and highly electronegative nature of fluorine, the oxyacids of the this element are much less common and less s
Molodets [167]

Answer:

HOFO = (0, 0, +1, -1)

Explanation:

The formal charge (FC) can be calculated using the following equation:

FC = V - N - \frac{1}{2}B

<u>Where:</u>

V: are the valence electrons

N: are the nonbonding electrons

B: are the bonding electrons

The arrange of the atoms in the oxyacid is:

H - O₁ - F - O₂

Hence, the formal charge (FC) on each of the atoms is:

H: FC = 1 - 0 - 1/2*(2) = 0            

O₁: FC = 6 - 4 - 1/2*(4) = 0        

F: FC = 7 - 4 - 1/2*(4) = +1

O₂: FC =  6 - 6 - 1/2*(2) = -1

We can see that the negative charge is in the oxygen instead of the most electronegative element, which is the F. This oxyacid is atypical.  

I hope it helps you!

3 0
3 years ago
A solution contains [Ba2+] = 5.0 × 10−5 M, [Zn2+] = 2.0 × 10−7 M, and [Ag+] = 3.0 × 10−5 M. Sodium oxalate (Na2C2O4) is slowly a
Jet001 [13]

Answer:

BaC₂O₄, then ZnC₂O₄, then Ag₂C₂O₄  

Explanation:

1. Calculate the equilibrium concentrations of oxalate ion

Let [C₂O₄²⁻] = c

(a) Barium oxalate

                 BaC₂O₄ ⇌   Ba²⁺   + C₂O₄²⁻

E/mol·L⁻¹:                   5.0 × 10⁻⁵     c

Ksp = [Ba²⁺][C₂O₄²⁻] = 5.0 × 10⁻⁵c = 1.5 × 10⁻⁸

c = (1.5 × 10⁻⁸)/(5.0 × 10⁻⁵) = 3.0 × 10⁻⁴ mol·L⁻¹

(b) Zinc oxalate

                ZnC₂O₄ ⇌   Zn²⁺   + C₂O₄²⁻

E/mol·L⁻¹:                 2.0 × 10⁻⁷      c

Ksp = [Zn²⁺][C₂O₄²⁻] = 2.0 × 10⁻⁷c = 1.35 × 10⁻⁹

c = (1.35 × 10⁻⁹)/(2.0 × 10⁻⁷) = 6.8 × 10⁻³ mol·L⁻¹

(c) Silver oxalate

                 Ag₂C₂O₄ ⇌   2Ag⁺   +   C₂O₄²⁻  

E/mol·L⁻¹:                      3.0 × 10⁻⁵       c

Ksp = [Ag⁺]²[C₂O₄²⁻] = (3.0× 10⁻⁵)²c = 9.0 × 10⁻¹⁰c = 1.1 × 10⁻¹¹

c = (1.1 × 10⁻¹¹)/(9.0 × 10⁻¹⁰) = 0.012 mol·L⁻¹

2. Decide the order of precipitation

BaC₂O₄ will precipitate when   c > 3.0 × 10⁻⁴ mol·L⁻¹

ZnC₂O₄ will precipitate when   c > 6.8 × 10⁻³ mol·L⁻¹

Ag₂C₂O₄ will precipitate when c > 0.028       mol·L⁻¹

This happens to be the order of increasing concentration of oxalate ion.

The order of precipitation is

BaC₂O₄, then ZnC₂O₄, then Ag₂C₂O₄

4 0
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8 0
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