It's difficult to write it down, but I'll attach you a good example of hydroboration of indene. I hope you'll find it helpful.
Answer:
0.302 moles
Explanation:
Data given
Mass of Pb(NO₃)₂ = 100 g
Moles of Pb(NO₃)₂ = ?
Solution:
To find mole we have to know about molar mass of Pb(NO₃)₂
So,
Molar mass of Pb(NO₃)₂ = 207 + 2[14 + 3(16)]
= 207 + 2[14 + 48]
= 207 + 124
Molar mass of Pb(NO₃)₂ = 331 g/mol
Formula used :
no. of moles = mass in grams / molar mass
Put values in above formula
no. of moles = 100 g / 331 g/mol
no. of moles = 0.302 moles
no. of moles of Pb(NO₃)₂ = 0.302 moles
A conjugate acid is a conjugate base with hydrogen ions attached to it. In this case, the conjugate base is the carbonate ion, CO₃⁻². This ion can have two hydrogen ions, so the conjugate acid is:
H₂CO₃
This compound is known as carbonic acid.
