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dusya [7]
3 years ago
9

Bromine is less electronegative than chlorine, yet methyl bromide and methyl chloride have very similar dipole moments. why? sel

ect the single best answer.
Chemistry
1 answer:
diamong [38]3 years ago
4 0
Bromine is less electronegative than chlorine, yet methyl bromide and methyl chloride have very similar dipole moments. This is because the bond distance in methyl bromide is more due to the large size of bromine atom.
Dipole moment is calculated by multiplying the charge on the atom with the bond distance.
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Tengo un volumen desconocido de gas mantenido a una temperatura de 115 K en un recipiente con una presión de 60.0 atm. Si al aum
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Which solute would be more effective at lowering the freezing point of water: MgCl2 and KNO3? Explain.
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Answer:

AlCl₃.

Explanation:

Adding solute to water causes depression of the boiling point.

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ΔTf = i.Kf.m,

where, ΔTf is the depression in freezing point.

i is the van 't Hoff factor.

van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

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(1) NaCl:

i for NaCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (NaCl) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

(2) MgCl₂:

i for MgCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

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(4) AlCl₃:

i for AlCl₃ = no. of particles produced when the substance is dissolved/no. of original particle = 4/1 = 4.

∴ ΔTb for (CoCl₃) = i.Kb.m = (4)(Kf)(1.0 m) = 4(Kf).

So, the ionic compound will lower the freezing point the most is: AlCl₃

4 0
3 years ago
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