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2 years ago

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What is the equation of the line in standard form? A. 3x + 5y = 1 B. x + 5y = 3 C. 5x + 3y = 1 D. x + 3y = 5

2 answers:

Pavel [41]2 years ago

7 0

The correct answer is A;

dalvyx [7]2 years ago

3 0

Slope (m) = y2-y1 / x2-x1
m = 2-(-1) / -3-2
m = 3/-5
m = -3/5

Calculation for b,
y = mx + b
-1 = -3/5(2) + b
1 = -6/5 + b
b = 1 +6/5 = 11/5

So, Equation in slope-intercept form would be: Y = -3/5x + 11/5

3/5x + y = 11/5 -----[Final Answer ]

Hope this helps!

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2 years ago

The graph of a line has a slope of -7 and a y intercept of (0,0). Rewrite the equation in standard form (Ax+By=C) with a positiv

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the equation of the line is 7x + y = 0 .

Step-by-step explanation:

in the standard form of the line that is Ax +By = C we can write it in the form of

By = C - Ax

$y = \frac{-A}{B}x +\frac{C}{B}$

which is in the form of $y = mx +c$

where m is the slope of the line and c is y intercept made by the line.

comparing $y = \frac{-A}{B}x +\frac{C}{B}$ and $y = mx +c$

we get that $\frac{-A}{B} =m$ and $\frac{-C}{B} = c$

since it is given that slope of the line is -7 therefore m = -7 and c = 0

therefore $\frac{-A}{B} =-7$ and $\frac{-C}{B} = 0$

therefore C = 0 , A = 7 and B = 1

therefore the equation becomes 7x + y = 0

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