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frutty [35]
2 years ago
15

The tip of a triangle is held 12.0 cm above the surface of a flat pool of water. A submerged swimmer in the pool sees the tip of

the triangle at what distance above the water? Let the indices of refraction nwater = 1.33 and nair = 1.00.
Physics
1 answer:
Rufina [12.5K]2 years ago
8 0

Answer: 9cm

Explanation:

Refractive index can also be defined as the ratio of the real depth to the apparent depth.

Given that the

Real depth = 12 m

Refractive index of water = 1.33

Refractive index of air = 1.00

nair/nwater = real depth/apparent depth

Substitute all the parameters into the formula

1.33/1 = 12/ apparent depth

Cross multiply

1.33 Apparent depth = 12

Apparent depth = 12/1.33

Apparent depth = 9.02 cm

Therefore,  A submerged swimmer in the pool sees the tip of the triangle at 9cm approximately distance above the water.

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Answer:

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A spring has a spring constant of 90N/m.How much potential energy does it store when stretched by 2 cm?
il63 [147K]

Answer:

The potential energy stored in the spring is 0.018 J.

Explanation:

Given;

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The potential energy stored in the spring is calculated as;

U = ¹/₂kx²

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An object is moving with constant non-zero velocity. Which of thw following statements about it must be true
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The net force on the object is zero.

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For the temperature 321 K, the temperature is 118.13 degree Fahrenheit.

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