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stira [4]
3 years ago
6

If two vectors are perpendicular to each other, how should you add them?

Physics
2 answers:
Aleksandr [31]3 years ago
8 0

Let us consider two vectors A and B.

As per the question, the two vectors are perpendicular to each other.

Hence the angle between them  \theta =90 degree

We are asked to calculate the resultant of these two vectors.

As per parallelogram law of vector addition, the resultant of two vectors are-

                      R=\sqrt{A^{2}+ B^{2}+2ABcos\theta

                                =\sqrt{ A^{2}+ B^{2}+2AB*cos90}    [cos90=0]

                                =\sqrt{ A^{2}+ B^{2}

This is the way by which we can add two perpendicular vectors.


olchik [2.2K]3 years ago
7 0

Answer:

use the pythagorean theorem

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A converging-diverging nozzle has a throat area of 10 cm2 and an exit area of 28.96 cm2 . A normal shock stands in the exit when
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The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

The given parameters:

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The ratio of the areas of the converging-diverging nozzle is calculated as follows;

= \frac{A}{A^*} \\\\= \frac{0.002896}{0.001} \\\\= 2.896

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\frac{P_o}{P_e} = 19.954 \\\\P_e = \frac{P_o}{19.954} \\\\P_e = \frac{101.325 \ kPa}{19.954} \\\\P_e = 5.08 \ kPa

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Learn  more about converging-diverging nozzle design here: brainly.com/question/13889483

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2 years ago
A sinusoidal electromagnetic wave is propagating in vacuum. At a given point P and at a particular time, the electric field is i
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Answer:

a

The direction of the wave propagation is the negative  z -axis

b

The amplitude of  electric and magnetic field are  A_E= 3.35*10^5 V/m ,

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Explanation:

According to right hand rule, your finger (direction of electric field) would be pointing in the positive  x-axis  i.e towards your right let your palms be face toward the direction of the magnetic field i.e negative y-axis  (toward the ground ) Then anywhere your thumb stretched out is facing is the direction of propagation of the wave here in this case is the negative  z -axis

             The Intensity of the wave is mathematically represented as

                          I = \frac{1}{2} c \epsilon _O E_{rms}^2

Given that I = 7.43 \frac{kW}{cm^2} =  7.43 \frac{*10^3}{*10^-{4} }= 7.43*10^7 \frac{W}{m^2}

Making E_{rms} the subject we have

                   E_{rms} = \sqrt{\frac{I}{0.5*c*\epsilon_o} }

Substituting values as given on the question

                E_{rms} = \sqrt{\frac{7.43 *10^7[\frac{W}{m^2} ]}{0.5 * 3.08*10^8 *8.85*10^{-12}} }

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The amplitude of the electric field is mathematically represented as

                  A_E = \sqrt{2} * E_{rms}

                         = \sqrt{2} * 2.37*10^5

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The amplitude of the magnetic field is mathematically represented as

                       A_M = \frac{A_E}{c}

Substituting value

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3 years ago
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