Which of the following is true about scientific knowledge?

FLASH FLOODS CAN CAUSE VEHICLES TO FLOAT AND FILL WITH WATER, TRAPPING AND DROWNING PEOPLE. WHILE ESPECIALLY DANGEROUS AT NIGHT

levacccp [35]

Answer:

FLASH FLOODS CAN CAUSE VEHICLES TO FLOAT AND FILL WITH WATER, TRAPPING AND DROWNING PEOPLE. WHILE ESPECIALLY DANGEROUS AT NIGHT AND IN DEEP WATER, EVEN ____ INCHES OF WATER CAN FLOAT SOME SMALL CARS.

The Answer is SIX Inches.

Explanation:

Flash floods: are short-term events and are associated with short, high-intensity rainfall which occur when creeks that are normally dry fill up and other creeks overflow. Densely populated areas have a high risk of flash floods. Water levels in flash floods can rise one foot in five minutes making Six inches of water able to reach the bottom of most passenger cars. Moving water will exert pressure on a car. The car floats downstream when stream force exceeds the friction force, the car will be carried when bouyancy force (which is the upward force exerted by any fluid upon a body placed in it) is greater than vehicle weight.

8 0

3 years ago

Question 8 of 10

Marrrta [24]

Answer:

C

Explanation:

If the theory were to be proved you you need to repeat the experiment over and over again so that way you can prove that it is true wuth the same results.

3 0

3 years ago

Read 2 more answers

A cyclist is riding his bike up a mountain trail. When he starts up the trail , he is going 8 m/s. As the trail gets steeper, he

Mrac [35]

Acceleration = (change in speed) / (time for the change)

change in speed = (speed at the end) - (speed at the beginning)

Our cyclist's change in speed = (3 m/s) - (8 m/s) = -5 m/s

Acceleration = (-5 m/s) / (60 seconds)

<em>Acceleration = -1/12 m/s²</em>

7 0

4 years ago

You are in charge of a cannon that exerts a force 11500 N on a cannon ball while the ball is in the barrel of the cannon. The le

IRISSAK [1]

Answer:

m = 7.48 kg

Explanation:

force (f) = 11,500 N

length of barrel (s) = 1.7 m

angle above the ground = 49.3 degrees

acceleration due to gravity (g) = 9.8 m/s^{2}

initial velocity (u) = 0 m/s

final velocity (v) = 72.3 m/s

mass (m) = ?

force = mass (m) x acceleration (a)

acceleration (a) = force / mass (m)

acceleration (a) = 11500 / m

applying the equation of motion $v^{2} = u^{2} + 2as$ , we can get the mass

$72.3^{2} = 0^{2} + (2 x \frac{11500}{m} x 1.7 )$

5227.3 = 0 + $\frac{39100}{m}$

m = $\frac{39100}{5227.3}$

m = 7.48 kg

5 0

3 years ago

Three carts of masses 4.0 kg, 10kg, and 3.0 kg move on a frictionless track with speeds of v1 = 5.0m/s, v2=3.0m/s, and v3=-3.6 m

gogolik [260]

2.24 m/s is the calculated velocity.

Initial velocity (u) squared plus two times the acceleration (a) times the displacement equals final velocity (v) squared (s). Final velocity (v) is equal to the square root of initial velocity (u) squared plus two times the acceleration (a) times displacement when v is the variable being solved for (s).

The cart's masses and speeds are known.

M1 = 4.00 kg, M2 = 10.0 kg, M3 = 3.00 kg, etc.

v1 = 5.00 m/s = 5.00 m/s, v2 = 3.00 m/s = 3.00 m/s, v3 = -4.00 m/s = 4.00 m/s, and m1v1+m2v2+m3v3 = (m1+m2+m3) v=d frac m 1v 1+m 2v 2+m 3v 3, where (m1+m2 + m3) is the product of (v1 v 1+m2v2+m3v3).

"m 1+m 2+m 3" is equivalent to "m 1+m2+m3/m1v 1+m2v2 +m3v3"

the three carts' final velocities are calculated as follows: v=d frac

{4.00kg\sdot5.00m/s+10.0kg\sdot3.00m/s-3.00kg\sdot4.00m/s} 4.24m/s = 4.50kg+10.0kg+3.00kg vs. 4.50kg+10.0kg+3.00kg

5.00m/s/4.00kg/5.00m/s+10.0m/s/3.00m/s/4.00m/s =2.24m/s.

2.24 m/s is the calculated final velocity.

Learn more about velocity here-

brainly.com/question/18084516

#SPJ9

7 0

2 years ago