Answer:
Tension, T = 2038.09 N
Explanation:
Given that,
Frequency of the lowest note on a grand piano, f = 27.5 Hz
Length of the string, l = 2 m
Mass of the string, m = 440 g = 0.44 kg
Length of the vibrating section of the string is, L = 1.75 m
The frequency of the vibrating string in terms of tension is given by :





T = 2038.09 N
So, the tension in the string is 2038.09 N. Hence, this is the required solution.
Vf = Final velocity.
Vi = initial velocity
a = acceleration.
t = time
Vf = Vi + at
Vf = 0 + (2 m/s^2)(3s)
Vf = 6 m/s south
Answer:
Levels of real per capita GDP are often cited to indicate living standards are higher in one country than another, and, by implication, that some systems of government or sets of government policies are better than others, but this measure of comparative living standards is so flawed as to be practically useless.
Explanation:
The magnitude of the force of friction is 6.1 N
Explanation:
The work done by a force when moving an object is given by the equation:
where
:
F is the magnitude of the force
d is the displacement
is the angle between the direction of the force and of the displacement
In this problem, we have:
W = -55.2 J (work done by the force of friction)
d = 8.98 m (displacement of the sled)
(because the force of friction acts opposite to the direction of motion)
By solving the equation for F, we find the magnitude of the force of friction on the sled:

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Answer:
0.46 g/mL
Explanation:
Density can be found using the following formula.

where <em>d</em> is density, <em>m</em> is mass, and <em>v</em> is volume.
We know that the object has a mass of 5.52 grams and a volume of 12 milliliters.
m=5.52 g
v=12 mL
Substitute these values into the formula.

Divide 5.52 by 12
5.52/12=0.46
d=0.46 g/mL
The density of the object is 0.46 g/mL, and option C is correct.