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g100num [7]
1 year ago
13

The air temperature is 20°C. You are swimming underwater when you hear a boat noise. Then, 3.5 s later, you hear a crash. If the

speed of sound in water is 1450 m/s, how long after you hear the crash does your friend on the dock beside you hear the crash?
Physics
1 answer:
GaryK [48]1 year ago
8 0

To answer this question we first need to know the distance from the crash to the swimmer and the dock.

The distance is given by:

d=vt

This means that the distance from the crash to the swimmer is:

d=(1450)(3.5)=5075

Therefore the crash happened at 5075 meters from the swimmer.

Now, to determine the time it takes the sound to reach the deck we need to determine the speed of sound on air at that temperature, this is given by:

v=331\sqrt[]{1+\frac{T}{273}}

then if the temperature is 20°C we have:

v=331\sqrt[]{1+\frac{20}{273}}=342.91

Then it takes the sound to reach the deck:

t=\frac{5075}{342.91}=14.8

Finally to determine the time it takes after you hear it we subtract the time it takes for you to hear it, then:

14.8-3.5=11.3

Therefore your friend hear the crash 11.3 seconds after you do.

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A raft with the area A , thickness= h and the mass 600 kg, Floats in still water with 7 cm
elena55 [62]

<span>In this problem, we need to solve for Bubba’s mass. To do this, we let A be the area of the raft and set the weight of the displaced fluid with the raft alone as ρwAd1g and ρwAd2g with the person on the raft, </span>where ρw is the density of water, d1 = 7cm, and d2= 8.4 cm. Set the weight of displaced fluid equal to the weight of the floating objects to eliminate A and ρw then solve for m.

<span>ρwAd1g = Mg</span>

ρw<span>Ad2g = (M + m) g</span>

<span>d2∕d1 = (M + m)/g</span>

m = [(d2<span>∕d1)-1] M = [(8.4 cm/7.0 cm) - 1] (600 kg) =120 kg</span>

This means that Bubba’s mass is 120 kg.

7 0
3 years ago
(III) A baseball is seen to pass upward by a window with a vertical speed of If the ball was thrown by a person 18 m below on th
Ghella [55]

Answer:

<em><u>Assuming that the vertical speed of the ball is 14 m/s</u></em> we found the given values:

a) V₀ = 23.4 m/s

b) h = 27.9 m

c) t = 0.96 s

d) t = 4.8 s

 

Explanation:

a) <u>Assuming that the vertical speed is 14 m/s</u> (founded in the book) the initial speed of the ball can be calculated as follows:  

V_{f}^{2} = V_{0}^{2} - 2gh

<u>Where:</u>

V_{f}: is the final speed = 14 m/s

V_{0}: is the initial speed =?

g: is the gravity = 9.81 m/s²

h: is the height = 18 m

V_{0} = \sqrt{V_{f}^{2} + 2gh} = \sqrt{(14 m/s)^{2} + 2*9.81 m/s^{2}*18 m} = 23.4 m/s  

b) The maximum height is:

V_{f}^{2} = V_{0}^{2} - 2gh

h = \frac{V_{0}^{2}}{2g} = \frac{(23. 4 m/s)^{2}}{2*9.81 m/s^{2}} = 27.9 m

c) The time can be found using the following equation:

V_{f} = V_{0} - gt

t = \frac{V_{0} - V_{f}}{g} = \frac{23.4 m/s - 14 m/s}{9.81 m/s^{2}} = 0.96 s

d) The flight time is given by:

t_{v} = \frac{2V_{0}}{g} = \frac{2*23.4 m/s}{9.81 m/s^{2}} = 4.8 s

         

I hope it helps you!    

3 0
3 years ago
Which of the following statements describes a perfectly inelastic collision?
Lyrx [107]

Answer: C

Explanation:

A collision in which the objects stick together is sometimes called “perfectly inelastic“

7 0
2 years ago
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