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marin [14]
3 years ago
7

An object is projected with initial speed v0 from the edge of the roof of a building that has height H. The initial velocity of

the object makes an angle α0 with the horizontal. Neglect air resistance. If α0 is 90∘, so that the object is thrown straight up (but misses the roof on the way down), what is the speed v of the object just before it strikes the ground?
Physics
1 answer:
Vsevolod [243]3 years ago
6 0

Answer:

Explanation:

Initial velocity u = V₀ in upward direction so it will be negative

u = - V₀

Displacement s = H . It is downwards so it will be positive

Acceleration = g ( positive as it is also downwards )

Using the formula

v² = u² + 2 g s

v² = (- V₀ )² + 2 g H

= V₀² + 2 g H .

v = √ ( V₀² + 2 g H )

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You are looking down on a 20 kg beam resting on a horizontal, frictionless surface. The beam is 2 m long and can pivot about one
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The angular speed of the rod after the impact is 1.49 rad/s

What is angular speed?

The rate of change of angular displacements is known as angular speed.

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Angular momentum is expressed as follows:

L=m*v*r

Here,

mass of beam, M =20 kg

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As here the Torque on which the system is zero implies that the angular momentum is conserved.

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Final angular momentum for rock: I(rf) = m*w*r^2

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Now, According to the conservation of momentum:

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The angular speed of the rod after the impact is 1.49 rad/s

Learn more about Angular speed here:

<u>brainly.com/question/14663644</u>

#SPJ4

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