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sattari [20]
3 years ago
15

Identifying Advantages of Parallel Circuits

Physics
2 answers:
I am Lyosha [343]3 years ago
8 0

Answer: The correct answers are B: If one bulb goes out, the other bulbs stay lit, and

C: If there is a break in one branch of the circuit, current can still flow through the other branches.

hope this helps you :3

melisa1 [442]3 years ago
3 0

Answer: If one bulb goes out the other bulbs stay lit.

If there is a break in one branch of the circuit, current can still flow through the other branches.

Explanation:

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2 equal charges, 27 micro Coulomb each, are separated by 5 cm. Find force between those.
padilas [110]

Answer:

The force between charges is  F= 2.624*10^3N.

Explanation:

The Coulomb force F between the two charges q_1 and q_2 separated by distance d is given by the equation

F = k\dfrac{q_1q_2}{d^2}

where k is the coulombs constant, and has the value

k= 9*10^9N\cdot C\cdot m^2.

Now in our case

q_1=q_2=27\mu C =27*10^{-6}C

and

d= 5cm =0.05m,

therefore, the Coulomb force between the charges is

F =( 9*10^9N\cdot C\cdot m^2)*\dfrac{(27*10^{-6}C)(27*10^{-6}C)}{(0.05m)^2}

\boxed{ F= 2.624*10^3N}

3 0
3 years ago
Two 5000-kg passenger cars roll without friction (one at 1 m/s, the other at 2 m/s) toward one another on a level track. They co
balu736 [363]

The combined momentum of the passengers is 5000 kgm/s.

<h3>Combined momentum of the passenger</h3>

The combined momentum of the passengers is calculated as follows;

P = mv1 + mv2

where;

  • m is mass of the passengers
  • v1 is velocity of the first passenger
  • v2 is velocity of the second passenger

P = m(v1 + v2)

P = 5000(-1 + 2)

P = 5000 kgm/s

Thus, the combined momentum of the passengers is 5000 kgm/s.

Learn more about momentum here: brainly.com/question/7538238

#SPJ1

5 0
2 years ago
The weight of any object due to the downward force of what?
melomori [17]
Isn't it "gravity" this would makes sense because grvaity difines weight
4 0
3 years ago
Read 2 more answers
A 10 Kg dog is running with a speed of 5.0 m/s what is the minimum work required to stop the dog
ra1l [238]

Answer:

25J

Explanation:

Given parameters:

Mass of the dog  = 10kg

Speed of the dog  = 5m/s

Unknown:

The minimum energy required to stop the dog  = ?

Solution:

The dog is moving with a kinetic energy and to stop the dog, an equal amount of kinetic energy generated must be applied to the dog.

 To find the kinetic energy;

        K.E  = \frac{1}{2} m v²

m is the mass

v is the velocity

Now insert the parameters and solve;

      K.E  =  \frac{1}{2}  x 10 x 5  = 25J

8 0
3 years ago
A human being can be electrocuted if a current as small as 55 mA passes near the heart. An electrician working with sweaty hands
evablogger [386]

Answer:

The lethal voltage for the electrician under those conditions is 126.5 V.

Explanation:

To discover what is the lethal voltage to the electrician we need to find out what is the voltage that produces 55 mA = 0.055 A when across a resistance of 2300 Ohms (Electrician's body resistancy). For that we'll use Ohm's Law wich is expressed by the following equation:

V = i*R

Where V is the voltage we want to find out, i is the current wich is lethal to the electrician and R is his body resistance. By applying the given values we have:

V = 0.055*2300 = 126.5 V.

The lethal voltage for the electrician under those conditions is 126.5 V.

4 0
3 years ago
Read 2 more answers
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