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max2010maxim [7]
4 years ago
5

Is the circuit you created a parallel, series or a series/parallel circuit? Support your answer with a description of this type

of circuit.
Physics
1 answer:
marysya [2.9K]4 years ago
5 0
It's a circuit wherein all the elements are in parallel and a resistance is fitted in series across which a voltmeter is connected to measure potential drop acrossR so as to find the current across the load that is bulb which connected to in series with the resistor
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Robbie found a rock in a stream. The rock was smooth and round. What MOST LIKELY caused this to happen?
Degger [83]

Answer:

C, weathering by the water.

Explanation:

While in the river, it scraps againsts other rocks and things, which causes it to change shape. For example be smoother and round.

7 0
3 years ago
Can any kind soul help me please​
Alex

Answer:

I) 420000J

ii)

Explanation:

(I) so you can use the formula for quantity of heat then substitute the values given

formula-Q=mc∆9

3 0
3 years ago
A bicyclist is travelling at 25 m/s when he begins to decelerate at -4m/s2 . How fast is travelling after 5 seconds
Umnica [9.8K]

Initial velocity (Vi) = 25 m/s

acceleration (a) = -4 m/s^{2}

time interval (t) = 5 sec

let us assume that final velocity after 5 sec be Vf

As acceleration is constant, we can apply the the equation of motion with constant acceleration i.e. V_{f} = V_{i} + at

Hence, V_{f} = 25 +(-4)(5) = 25 -20 = 5 m/s

so, the velocity of bicyclist will be 5 m/s after 5 sec

7 0
3 years ago
What is the lens equation?
Strike441 [17]
The lens equation gives d relation between focal length, object distance n image distance.

1/f = 1/v + 1/u

seldon
7 0
3 years ago
Read 2 more answers
An elite tour de france cyclist can maintain an output of 420 watts during a sustained climb. at this output power, how long wou
julia-pushkina [17]
<span>2002 seconds, or 33 minutes, 22 seconds. First, let's calculate how many joules it will take to lift 78 kg against gravity for 1100 meters. So: 78 kg * 9.8 m/s^2 * 1100 m = 840840 kg*m^2/s^2 Now a watt is defined as kg*m^2/s^3, so a division of the required joules should give us a convenient value of seconds. So: 840840 kg*m^2/s^2 / 420 kg*m^2/s^3 = 2002 seconds. And 2002 seconds is the same as 33 minutes, 22 seconds.</span>
7 0
3 years ago
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