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Natali [406]
3 years ago
9

Which is NOT a component of a nucleotide?

Physics
1 answer:
Nitella [24]3 years ago
6 0

Answer:

Lysine

Explanation:

A nucleotide is a combination of a nitrogen base, pentose sugar, and phosphate. Adenine, Guanine (purines) and Thymine (pyrimidine) are nitrogen base. Lysine is the amino acid.

Hope it helps,Pls Mark as Brainliest!!

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The recessive trait will always show up

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A 1.2 kg basketball is thrown upwards. What is the potential energy of the basketball at the top of its path if it reaches a hei
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Answer:

Answer is 183.6 J

Explanation:

Using the Physics reference sheet the formula for Potential energy is

(mass) x (gravity) x (height)

Mass= 1.2

Gravity I used is 9.81 (use 10 to get the answer most schools use)

Height= 15.6

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Differentiate between a derived quantity and a derived unit.
Inessa [10]

Explanation:

Derived quantities are quantities dependent on fundamental quantities while derived units are the units of these quantities

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Determine the MA based on the diagram below.
artcher [175]
There are two things that you should remember while dealing with the "Lever Mechanical Advantage" problems:

1) The Effort Arm;
2) The Resistance Arm.

Some books label the Effort Arm as in-lever arm and the Resistance Arm as out-lever arm. (Physics Jargon that you need to remember in order to solve problems)

The Effort Arm is that "part" of the lever where the force can be applied. The Resistance Arm is where some mass is placed. In the diagram, as you can see, the mass is placed on one arm of the lever. Therefore, it is the Resistance Arm.

Now the formula for the "Mechanical Advantage(MA)" is:
MA =  \frac{L_{e} }{ L_{r} }

Where L_{e} is the length of the Effort Arm(the subscript "e" stands for Effort), and L_{r} stands for the length of the Resistance Arm(here "r" stands for Resistance).

Plug in the values:

L_{e} = 15m.
L_{r} = 7m.

Therefore, L_{e} / L_{r} = 15/7 = 2.143 = MA

The correct answer is option C(2.14).

-i

3 0
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A 70.0-kg person throws a 0.0430-kg snowball forward with a ground speed of 32.0 m/s. A second person, with a mass of 58.5 kg, c
Aleks04 [339]

Answer:

The velocities of the skaters are v_{1} = 3.280\,\frac{m}{s} and v_{2} = 0.024\,\frac{m}{s}, respectively.

Explanation:

Each skater is not under the influence of external forces during process, so that Principle of Momentum Conservation can be used on each skater:

First skater

m_{1} \cdot v_{1, o} = m_{1} \cdot v_{1} + m_{b}\cdot v_{b} (1)

Second skater

m_{b}\cdot v_{b} = (m_{2}+m_{b})\cdot v_{2} (2)

Where:

m_{1} - Mass of the first skater, in kilograms.

m_{2} - Mass of the second skater, in kilograms.

v_{1,o} - Initial velocity of the first skater, in meters per second.

v_{1} - Final velocity of the first skater, in meters per second.

v_{b} - Launch velocity of the meter, in meters per second.

v_{2} - Final velocity of the second skater, in meters per second.

If we know that m_{1} = 70\,kg, m_{b} = 0.043\,kg, v_{b} = 32\,\frac{m}{s}, m_{2} = 58.5\,kg and v_{1,o} = 3.30\,\frac{m}{s}, then the velocities of the two people after the snowball is exchanged is:

By (1):

m_{1} \cdot v_{1, o} = m_{1} \cdot v_{1} + m_{b}\cdot v_{b}

m_{1}\cdot v_{1,o} - m_{b}\cdot v_{b} = m_{1}\cdot v_{1}

v_{1} = v_{1,o} - \left(\frac{m_{b}}{m_{1}} \right)\cdot v_{b}

v_{1} = 3.30\,\frac{m}{s} - \left(\frac{0.043\,kg}{70\,kg}\right)\cdot \left(32\,\frac{m}{s} \right)

v_{1} = 3.280\,\frac{m}{s}

By (2):

m_{b}\cdot v_{b} = (m_{2}+m_{b})\cdot v_{2}

v_{2} = \frac{m_{b}\cdot v_{b}}{m_{2}+m_{b}}

v_{2} = \frac{(0.043\,kg)\cdot \left(32\,\frac{m}{s} \right)}{58.5\,kg + 0.043\,kg}

v_{2} = 0.024\,\frac{m}{s}

5 0
3 years ago
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