Isaac Newton discovered that __________ is a mixture of lights of many different wavelengths.

Two particles have a mass of 8kg and 12kg, respectively. if they are 800mm apart, determine the force of gravity acting between

natima [27]

The magnitude of the force of gravity acting between the particles is:
$F=G\frac{m_1.m_2}{d^2}$
The weight of each particle is:
$P=mg$
Now let's plug in the numbers knowing that $G=6.67\times10^{-11}$ , $g=9.81$ , $d=0.8$ and m1 and m2 are already given in kilograms. We get then:
$P_1=m_1.g=78.48$ N
$P_2=m_2.g=117.72$ N
$F=G\frac{m_1.m_2}{d^2}=1.00\times10^{-8}$ N

This results shows us why we don't often see objects being attracted to each other, their mass is too small compared to the earth gravitational pull.

8 0

3 years ago

A visitor to the observation deck of a skyscraper manages to drop a penny over the edge. As the penny falls faster, the force du

pentagon [3]

If a coin is dropped at a relatively low altitude, it's acceleration remains constant. However, if the coin is dropped at a very high altitude, air resistance will have a significant effect. The initial acceleration of the coin will be the greatest. As it falls down, air resistance will counteract the weight of the coin. So, the acceleration will decrease. Although the acceleration decreases, the coin still accelerates, that is why it falls faster. When the air resistance fully counters the weight of the coin, the acceleration will become zero and the coin will fall at a constant speed (terminal velocity). So, the answer should be, The acceleration decreases until it reaches 0. The closest answer is.
a. The acceleration decreases.

8 0

3 years ago

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How large an expansion gap should be left between steel railroad rails if they may reach a maximum temperature 30.0°C greater th

irina [24]

Answer:

Explanation:

<u>Thermal Expansion</u>

It's the tendency that materials have to change its size and/or shape under changes of temperature. It can be in one (linear), two (surface) or three (volume) dimensions.

The formula to compute the expansion of a material under a change of temperature from $T_o$ to $T_f$ is given by.

$\Delta L=L_o.\alpha .(T_f-T_o)$

Where Lo is the initial length and $\alpha$ is the linear temperature expansion coefficient, which value is specific for each material. The data provided in the problem is as follows: