Answer:
Due to energy loss while collision ball will not reach to same height while if there is no energy loss then in that case ball will reach to same height
Explanation:
As we know that initially ball is held at height h = 40 cm
So here we can say that kinetic energy of the ball is zero and potential energy is given as
now when strike with the ground then its its fraction of kinetic energy is lost in form of other energies
So the ball will left rebound with smaller energy and hence it will reach to height less than the initial height
While if we assume that there is no energy loss during collision then in that case ball will reach to same height again
Answer:
55 ft/s
Explanation:
A₁ = Area of rectangular cross-section at input side = 1.5 x 11 = 16.5 ft²
A₂ = Area of rectangular cross-section at far end = 1.5 x 6 = 9 ft²
v₁ = speed of water at the input side of channel = 30 ft/s
v₂ = speed of water at the input side of channel = ?
Using equation of continuity
A₁ v₁ = A₂ v₂
(16.5) (30) = (9) v₂
v₂ = 55 ft/s
Can cause children into getting cyber bullying, being a thief, sexual behavior, anxiety, and depression
<u>Answer:</u>
<em>The outside edge of a spinning compact disc moves with a higher velocity than the inner track of the disc.</em>
<u>Explanation:</u>
Here the compact disc undergoes rotational motion about a fixed axis which is its centre in this case. The particles in rotational motion have angular velocity which is given by the equation
ω = ∅/t
Where θ is the angular displacement and t is the time.
The transnational speed of a particle which is in circular motion is given by the equation
v = rω
r is the distance of the point from the rotation centre
The transnational speed of the particles is merely determined by their distance from the centre in this case. It is due to the equality of angular velocity of all the points.
The distance of the outer edge of the compact disc from its rotational centre is larger than the distance of inner edge from the rotational centre. Thus the farther edge of a spinning disc moves faster than the nearer edge.
