Question

A roller coaster has a mass of 275 kg. It sits at the top of a hill with height 85 m. If it drops from this hill, how fast is it going when it reaches the bottom? (Assume there is no air resistance or friction.)

Answer 1

Explanation:

Given that,

Mass of the roller costar, m = 275 kg

It sits at the top of a hill with height 85 m, h = 85 m

We need to find the speed with which it is going when it reaches the bottom. It can be calculated using the conservation of energy as :

$\dfrac{1}{2}mv^2=mgh$

g is the acceleration due to gravity

$v=\sqrt{2gh}$

$v=\sqrt{2\times 9.8\times 85}$

v = 40.81 m/s

So, the speed of the roller coaster when it reaches the bottom is 40.81 m/s. Hence, this is the required solution.

Answer 2

kinematic equation

v squared = u squared + 2 a x s

v= sq root (0 + 2 10 x 65)

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