A roller coaster has a mass of 275 kg. It sits at the top of a hill with height 85 m. If it drops from this hill, how fast is it
2 answers:
Explanation:
Given that,
Mass of the roller costar, m = 275 kg
It sits at the top of a hill with height 85 m, h = 85 m
We need to find the speed with which it is going when it reaches the bottom. It can be calculated using the conservation of energy as :
g is the acceleration due to gravity
v = 40.81 m/s
So, the speed of the roller coaster when it reaches the bottom is 40.81 m/s. Hence, this is the required solution.
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The induced emf in the loop is -1500 μ V or - 0.0015 V .
According to the question
A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t.
i.e
Magnetic field (B) = 0. 50 T
Area of circle or loop =
Now,
The area of the loop decreases at a rate of 3. 0 × 10⁻³ m/s
i.e
dA = 3. 0 × 10⁻³ meter²
dt = 1 sec
As per the formula of Induced e.m.f in the loop
emf is dependent on number of turns of coil, shape of the coil, strength of magnet and speed with which magnet is moved. Emf is independent of resistivity of wire of the coil.
where A is the area of the loop.
Now ,
Substituting the values in the formula
e = - 0.0015 V
OR
e = -1500 * 10⁻⁶ V
e = -1500 μ V
Negative just signifies emf will such be induced that current induced will oppose change in magnetic field though it
To know more about induced emf here:
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