If an 800.0 Kg sports car slows to 8.0 m/s in the forward direction to check out an accident scene and a 1200.0 kg pick-up truck
behind them continues traveling at 15.0 m/s forward, with what velocity will the two move if they lock bumpers after a rear-end collision
1 answer:
Answer:
<h2>
<u>12.2m/s</u></h2>
Explanation:
Step one:
given data
mass m1=800kg
velocity v1=8m/s
mass m2= 1200kg
velocity v2=15m/s
Note: the two bodies move with the same velocity after collision, hence the common velocity is v=?
Step two:
the expression for the total momentum is
m1v1+m2v2=v(m1+m2)
substituting we have
800*8+1200*15=v(800+1200)
6400+18000=v(2000)
24400=2000v
divide both sides by 2000 to find v
v=24400/2000
v=12.2m/s
<u>Their common velocity is 12.2m/s</u>
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