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Elan Coil [88]
3 years ago
14

If an 800.0 Kg sports car slows to 8.0 m/s in the forward direction to check out an accident scene and a 1200.0 kg pick-up truck

behind them continues traveling at 15.0 m/s forward, with what velocity will the two move if they lock bumpers after a rear-end collision
Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

<h2><u>12.2m/s</u></h2>

Explanation:

Step one:

given data

mass m1=800kg

velocity v1=8m/s

mass m2= 1200kg

velocity v2=15m/s

Note: the two bodies move with the same velocity after collision, hence the common velocity is v=?

Step two:

the expression for the total momentum is

m1v1+m2v2=v(m1+m2)

substituting we have

800*8+1200*15=v(800+1200)

6400+18000=v(2000)

24400=2000v

divide both sides by 2000 to find v

v=24400/2000

v=12.2m/s

<u>Their common velocity is 12.2m/s</u>

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Suggest one reason why the bricklayer needs a higher energy diet than the computer operator
sashaice [31]

Answer:

he needs more because he is doing more exercise this means he is working his body more and he needs more energy than someone he is sitting in an office. The computer operator would not need as much energy as the brick layer.

7 0
3 years ago
Which part of the heating curve corresponds with the heating of liquid water?
salantis [7]

Answer: the part of the heating curve corresponds to showing how the temperature changes as a substance for a constant rate.

Explanation: Let me know if you need any details!

8 0
3 years ago
Read the scenario and solve these two problems.
Burka [1]

Answers:

a) 5400000 J

b) 45.92 m

Explanation:

a) The kinetic energy K of an object is given by:

K=\frac{1}{2}mV^{2}

Where:

m=12000 kg is the mass of the train

V=30 m/s is the speed of the train

Solving the equation:

K=\frac{1}{2}(12000 kg)(30 m/s)^{2}

K=5400000 J This is the train's kinetic energy at its top speed

b) Now, according to the Conservation of Energy Law, the total initial energy is equal to the total final energy:

E_{i}=E_{f}

K_{i}+P_{i}=K_{f}+P_{f}

Where:

K_{i}=5400000 J is the train's initial kinetic energy

P_{i}=0 J is the train's initial potential energy

K_{f}=0 J is the train's final kinetic energy

P_{f}=mgh is the train's final potential energy, where g=9.8 m/s^{2} is the acceleration due gravity and h is the height.

Rewriting the equation with the given values:

5400000 J=(12000 kg)(9.8 m/s^{2})h

Finding h:

h=45.918 m \approx 45.92 m

7 0
3 years ago
Read 2 more answers
An airplane is being pushed West by its engines with a force of 350 N as it starts to take off the runway at the Atlanta airport
Marizza181 [45]

Answer:

option C

Explanation:

given,

Force by the engine on plane in West direction = 350 N

Frictional force on the runway = 100 N in east

force exerted by the wind = 100 N in east

net force and direction = ?

consider west to be positive and east be negative.

when airplane will be moving there will be frictional as well as wind resistance will be acting in opposite direction of airplane

Net force = 350 N - 100 N - 100 N

                 = 150 N

as our answer comes out to be positive so the airplane will be moving in West

hence, the correct answer is option C

8 0
3 years ago
The air in a room has a pressure of 1 atm, a dry-bulb temperature of 24°C, and a wet-bulb temperature of 17°C. Using the psychro
Licemer1 [7]

Answer:

Given that

Dry-bulb temperature(T) =24°C

Wet-bulb temperature(Tw) = 17°C

Pressure ,P = 1 atm

As we know that  psychrometric chart are drawn at constant pressure.

From the diagram

ω= specific humidity

Lets take these two lines   Dry-bulb temperature(T) line and Wet-bulb temperature(Tw) cut at point P

From chart at point P

a)

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b)

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h=47.59 KJ/kg

c)

The relative humidity, RH

RH= 49.58 %

d)

Specific volume ,

v= 0.853 m³/kg

5 0
3 years ago
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