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spin [16.1K]
4 years ago
5

The volume of the lung 0.0024m^3 following exhalation and the pressure is 101.70KPa. Calculate the volume of the lungs during in

halation if the pressure falls to 84.16KPa
Physics
1 answer:
Mekhanik [1.2K]4 years ago
5 0

According to Boyle-Mariotte:

p₁V₁=p₂V₂=>V₂=p₁V₁/p₂= 0.0024*101.70/ 84.16=0.0028 m³

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Learn more about Hubble's law here: brainly.com/question/19819028

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